twinsdragon

That is a very simple mathematics question.
  V, o/ B1 O# d# N8 l+ e$ Z/ QLet x = Male, y = Female, z = Child5.39.217.76$ X$ o# v5 n2 c/ Z1 b1 z
6x + 3y + z/2 = 100   Formula 15.39.217.76" w: V0 ~( K! s2 z* S% ^+ B
x + y + z = 100    Formula 2tvb now,tvbnow,bttvb# Y5 U' r' |! l; R# L; _& i
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3/ D+ `9 L  l7 {5 l  f. D7 H
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
3 J* M7 I! v/ p5 J% P0 XFormula 4 can change into 11x + 5y = 100 Formula 5+ [$ `. d5 q, F6 ~& f
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
' e: Y! E& a7 L! K# GAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇5 l2 |: Q% n; x8 s
Eventually, the answer is 20 female and 80 children and no male.