twinsdragon

That is a very simple mathematics question.
1 `0 v7 y) p! ^公仔箱論壇Let x = Male, y = Female, z = Child
# Z0 a1 [/ B& Q! C, h1 `3 Utvb now,tvbnow,bttvb6x + 3y + z/2 = 100   Formula 1
" U3 A0 Y/ e9 J: M# q, Z& r9 F9 n  B5.39.217.76x + y + z = 100    Formula 2
) K' q9 ^3 m0 S# @4 k4 X6 D公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3; ^& d# D+ ?4 o* H! P0 s
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
3 W7 ~* Z, Z# v/ P) u0 j/ [Formula 4 can change into 11x + 5y = 100 Formula 5
# s5 {5 E% \1 f* RTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
2 }1 t2 l0 T5 _+ Q: Ftvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
  F1 `4 ?$ r+ v- `  C4 q6 [6 SEventually, the answer is 20 female and 80 children and no male.