twinsdragon

That is a very simple mathematics question.
0 ~1 m8 B3 U9 e1 Z5.39.217.76Let x = Male, y = Female, z = Child
$ Y: a  f( _3 m5.39.217.766x + 3y + z/2 = 100   Formula 1TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。9 c3 K& b, ~" V, D" [) q6 V
x + y + z = 100    Formula 2
3 y+ n. _4 [5 \+ k9 L( D* L! y6 ?' P1 hSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
! `/ t5 u" A5 N# f5 U  O: ~9 ISub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
+ X* d1 e; O; o; ?& i6 k9 ]tvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 55.39.217.767 Y: F/ P3 U) J3 E, a3 n8 b
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
3 @" I( p5 ?' {And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
0 H6 N  j% N% E! I% c; K6 S2 `TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male.