twinsdragon

That is a very simple mathematics question.
6 n" ]4 L/ H# A+ Q5.39.217.76Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb7 N! Z* Z  L2 u' ^
6x + 3y + z/2 = 100   Formula 1
" z- S/ S1 s8 X7 D  F. p5.39.217.76x + y + z = 100    Formula 2
* v# z, F$ N1 R- q5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
. r7 B8 V- Z& X0 NTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
. ~: E! ?2 C5 }tvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5
5 e- p; M% }- J  v7 nIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
! ^) a4 u3 l+ f+ ~9 I- o3 Q* @And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.6 x2 U1 `' Z3 I6 ?! H) v! X- X6 a
Eventually, the answer is 20 female and 80 children and no male.