That is a very simple mathematics question.
4 u, T4 t' m! i+ }Let x = Male, y = Female, z = Child
* y! R2 ^" b( w7 K5 |. R( Ftvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 15.39.217.76+ [1 f" P# p7 G7 _# R" T$ n4 M# G! V3 v
x + y + z = 100 Formula 2
5 A, ~ v- K) x0 O Q& u9 ]Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.762 ~1 E" K# w/ y! G0 w
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇! y* N$ b1 _1 {& I8 k; K l1 {
Formula 4 can change into 11x + 5y = 100 Formula 5
1 ~9 g! V" O; l; c公仔箱論壇In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.* b% P# Z& g: P
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.! u5 c( o. T+ E
Eventually, the answer is 20 female and 80 children and no male. |