That is a very simple mathematics question.# e& i% A- ?5 k# N
Let x = Male, y = Female, z = Child9 P! W+ K3 Y# t
6x + 3y + z/2 = 100 Formula 1
. P8 z2 {; Q- m! d; N& f5.39.217.76x + y + z = 100 Formula 2
% Q9 v. M/ T4 T: g" j6 ~TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
) @/ [- G; ]( o# I/ |5.39.217.76Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ q$ q; Z- F; A- P' W, x# j* xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5
& l: _: |0 I! v% ltvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
/ |8 m8 d4 E) U+ s0 E% s, C5 [And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
' C: D9 |! ?6 A, l. y# [公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |