That is a very simple mathematics question.
, }& f3 z( N4 ^4 L4 @. U, v% VLet x = Male, y = Female, z = Child
# }" h, Q. h$ p' i( p6x + 3y + z/2 = 100 Formula 1
9 C7 }, O! c6 T, H5.39.217.76x + y + z = 100 Formula 25.39.217.76/ C d( c; ^: B1 E
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
1 u. Y0 r# b6 Z1 C1 v; A7 o4 T- otvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
/ k% y0 N3 a( pTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.76/ `/ F5 n0 D% K
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 y" o" }2 n) G8 \公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
0 R7 @! i R0 R7 P5.39.217.76Eventually, the answer is 20 female and 80 children and no male. |