That is a very simple mathematics question.( c$ \* F# @( \: d
Let x = Male, y = Female, z = Child# Y5 b9 O* z0 p( @# f: t& `4 i
6x + 3y + z/2 = 100 Formula 1
: l% G! _: v9 ~- i2 C; f5.39.217.76x + y + z = 100 Formula 2
; y! g( x) [3 e ]1 e4 t& ASimplify Formula 2 into z, we get z = 100 - x - y Formula 3
& F6 ]/ S5 G% | N; s+ y3 YSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
( {$ e8 ?' w( y4 _' t* C' p3 J9 j: Wtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 C+ T# s7 e; f8 A0 x$ S
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.. \: Q2 }2 y& }% ?+ B
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
1 y* v1 J5 d. eTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Eventually, the answer is 20 female and 80 children and no male. |