fishy129

第2的....直覺告訴我

252677071

0000000000

a1206bc

友華

palmkaky

我已經想很久了公仔箱論壇8 U7 S; D/ a6 y  Y, j0 S
實在太難- v9 Z# M$ l; \+ K) D- P8 B
只好來看答案了

kurakinami

no2,,3,4應該沒那麼容易死瓜

loveallcar

number 4 has the best chance to live
% g7 p: k* m% U5 P5.39.217.76assume number 1, 2, 3 and 4, pick number a, b, c and d.公仔箱論壇8 |6 E+ c+ o9 C" s9 L3 d' b
number 4 knows how many left in the bag which is 100-a-b-c
; C* J9 J" e6 i/ E2 l- V1 Mtake the average of (100-a-b-c)
! X- X5 L" d( `% Y1 i8 Btvb now,tvbnow,bttvbthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
. [; l1 b& H5 L1 j0 R公仔箱論壇and number 4 can squeeze himself into the average and what number 5 picks.
* E3 F! q3 A  [; S6 {TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。so number 4 will have the best chance.
: @+ m, h3 E( z公仔箱論壇+ j2 B) w# s3 F9 H+ [
i hope this is a good logic hehe

kyle326

同意楼上 Number 4 係最安全！！ Number5 係一定死咖了！！ 不过我就唔知 Number 1，2，3 边个唔好彩jie ！！
5 G& m- ^+ U# ]" j/ [2 w玩心理咖话！！ 5号 好大压力！！ 因为就算佢知剩下几多豆 佢豆好难判断所以！！！公仔箱論壇' b0 q# ]+ z% i! C4 z7 }9 {
5.39.217.765 H1 ?* z+ x" h2 @% g& Q6 G" r* `% `
如果绝D咖哇！！  全部豆色！！！ 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈！！！！（因为一人要一粒 所以佢哋冇得拣  只可以摞一粒！！）

leona

想不到！！答案呢？

a01882003

應該是第三ㄍ吧

Allan

no 2 !!! no 2 !!!                  
% \& t0 k& j  _- Y3 R1 M1 h7 L
$ P2 g# x; X9 W* Z! @3 ]5.39.217.76             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
# Y; b0 b8 D& y0 j  F4 `9 Y5.39.217.76So they will all die !!                                                      公仔箱論壇/ m, n& J8 E3 M5 b
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。3 ~/ c+ {" A/ T. E& c* u; G
tvb now,tvbnow,bttvb& |) u1 b) J3 r! Y# }

( l- d, _' G2 h5 q* HTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。tvb now,tvbnow,bttvb7 P0 `% {) n! n$ m9 V

9 i# I2 C5 g8 M* rJust Joking !!!

nightrider

The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
& h2 B3 k. K2 o! m( p. a5.39.217.76+ ^1 J1 _( C: I4 R& O& x
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  ( Z8 e+ A: J' M/ D3 z7 Q
5.39.217.764 [4 j8 x; M. e- J
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
# Q! Z$ r6 J* S/ L3 M$ |公仔箱論壇
, F# c5 o  j- A! _# X# D( o#3 did the obvious choice 40 divided by 2 =20, so he picked 20
. W( X  ~# d2 M: t# Q* t. ?2 G2 ~+ Y- C1 `  {; J2 n: @& y
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
3 r2 g, D: g4 N% k% btvb now,tvbnow,bttvb公仔箱論壇! X2 s- z/ W0 g% v% O' @" [
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
' ~9 V1 s6 N( y' C' C5.39.217.76
/ @( m7 ^0 r4 X) dEnded all have the same number and all died.

chester1109

我猜NO4，
/ c+ Y: T7 q% |8 |公仔箱論壇因為他可以取前面三位豆子的平均數，公仔箱論壇% ~$ L) v( V1 J
也可以防止豆子不夠讓NO5墊底。

289675283

最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
1 T" h" a7 _! W/ Q# O公仔箱論壇
8 C5 {- o" u% Y/ q7 s+ t0 ltvb now,tvbnow,bttvb[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]

dj_feng

[-X  所謂IQ題唔喺可以用普通思維gē，5.39.217.76; \+ V1 u, Z/ K

! f7 C0 D* ]6 U2 t9 [0 v! Y+ W# Z公仔箱論壇答案應該喺 ：抓豆子不多不少的那個囚犯存活率是最大的

hhhaaannn

想想