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第2的....直覺告訴我
0000000000
友華
我已經想很久了tvb now,tvbnow,bttvb0 @8 {* L: h. d7 `3 n
實在太難
7 C& |- n" [8 K公仔箱論壇只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
1 p- g; y5 s1 uTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。assume number 1, 2, 3 and 4, pick number a, b, c and d.
: @3 O8 \& M8 E* b2 Mnumber 4 knows how many left in the bag which is 100-a-b-c
8 R5 b6 t$ k/ p# ]& _4 ?公仔箱論壇take the average of (100-a-b-c)tvb now,tvbnow,bttvb) u" f' z1 T* A1 Y. Z  A4 E
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)/ H  m4 l, f" r. _
and number 4 can squeeze himself into the average and what number 5 picks.% |# ~. j  G# K# N
so number 4 will have the best chance.
5 ?: M3 C. T2 l; t$ p. G$ OTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ K3 |/ S6 Q+ \! O5 ^% ^- C
i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
' [  u! h- r" B5 @% M2 o3 M公仔箱論壇玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!( z8 {) v( e0 j. _! l  E2 U# E1 j

' [# A9 o+ K( x5.39.217.76如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
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& ^1 d& C, Y7 G4 {% p5 g; ktvb now,tvbnow,bttvb             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
/ B% k: m* b8 ^4 U: R5 GTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。So they will all die !!                                                      
! U3 ^, t5 z& n( T) ?% F公仔箱論壇
) x9 a, u8 c, }5 Z公仔箱論壇
" I9 ~* G# O  s+ F% ]$ r; n公仔箱論壇
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9 [% [/ L& D, l公仔箱論壇
8 M) }8 }5 Y! e/ ^0 _; YJust Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.7 a, l; E5 w: [( w0 \6 p0 Z
5.39.217.76! x/ V0 H2 |% ]3 f4 Y$ |
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
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6 {1 T8 X' A7 a& SNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.公仔箱論壇0 ?- Y- O& F. b
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 E) H- X8 f) z5 W: o) g9 P+ K  A
#3 did the obvious choice 40 divided by 2 =20, so he picked 20
: K9 a2 _" D7 |& F4 W; G; p1 c公仔箱論壇
4 Q3 U% K& a* k( o7 M* N5.39.217.76#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
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#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
' p! j" j' ~. _公仔箱論壇5.39.217.76" ~$ C4 T7 [. l, D. n0 o
Ended all have the same number and all died.
我猜NO4,7 ~( u2 B1 x$ {1 F' T/ u$ `0 f" a
因為他可以取前面三位豆子的平均數,
! V) B* v% X" ^4 L也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅6 p4 U* a( }  t1 |* ]8 w* Z9 A
5.39.217.76! a4 W9 T7 b+ Q5 t: v! c0 C
[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,公仔箱論壇7 Z: E3 P4 G& g% r/ ?/ M) ^
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。- U7 j$ C: `7 w  n
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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