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第2的....直覺告訴我
0000000000
友華
我已經想很久了
3 C$ a1 @& m; ]4 k- G1 Jtvb now,tvbnow,bttvb實在太難公仔箱論壇/ V6 f& x, L6 {! A* C  W+ v
只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
/ E0 g" M' ~! c: M3 [  }5.39.217.76assume number 1, 2, 3 and 4, pick number a, b, c and d.
* ^5 r1 r# x2 F: Z& M. U' j. Lnumber 4 knows how many left in the bag which is 100-a-b-c
! e/ l3 Y& P0 O4 Q1 i7 T2 a5.39.217.76take the average of (100-a-b-c); M+ K* O3 f% c1 T# G
then number 4 knows a or b or c must be greater or less than average of (100-a-b-c): i8 c/ Y1 b# N) L- R
and number 4 can squeeze himself into the average and what number 5 picks.
5 d/ D, |8 f8 J1 UTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。so number 4 will have the best chance.tvb now,tvbnow,bttvb: _' V6 _3 y: A% Z
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i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 t# u  A) ^1 d  m. w
玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!
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3 u. L; I+ {0 K' ~/ {# s公仔箱論壇如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
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' ~' A; Q$ I0 F  i& e+ OTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18. 5.39.217.76. R' ]  y( l: I9 o8 O
So they will all die !!                                                      . r! k" ?2 w" |' T* b
tvb now,tvbnow,bttvb" G0 o* C/ `" H0 \: `, ^( b

4 y9 u' g3 g4 P4 ]tvb now,tvbnow,bttvbtvb now,tvbnow,bttvb9 F/ v# L' g! W: `

# O! Q0 l7 N5 z+ FTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。tvb now,tvbnow,bttvb$ |) S9 w2 f( |3 ~" w: E" A  B
Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.6 f6 P. m) C$ a! Y4 E6 b& C
5.39.217.768 V$ V# V/ X. T7 g$ A
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
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6 ~1 i3 u  n# sTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.
( u7 {) _( a# w! N' V5 H$ t: e5.39.217.76tvb now,tvbnow,bttvb2 p1 [% T& w4 o7 J. B
#3 did the obvious choice 40 divided by 2 =20, so he picked 20
; X( J: E/ ?* Y$ R$ G; w7 w5.39.217.765.39.217.76' D- l2 [% X& k
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.5.39.217.76: A1 W. h; F1 \0 Z( b! ?
tvb now,tvbnow,bttvb" u" V- F9 i1 l+ r
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.5.39.217.76& }. Z* J9 e4 s9 v6 Z" }& z

7 L4 }0 T) P5 \- C9 eEnded all have the same number and all died.
我猜NO4,1 T) \+ l1 ^1 ]% V( B
因為他可以取前面三位豆子的平均數,
2 |( b; H1 M+ n) h也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
9 S# u  A! \* \' N& Ftvb now,tvbnow,bttvb
/ j9 d. P8 C, q9 N[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
$ s6 o4 \- @: Z# b2 g5.39.217.769 d" t- x7 S( Z
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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