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[IQ題] 一道真正難倒億人的智力題

一道真正難倒億人的智力題
# Y( X( e. W' [! t6 A6 eTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
2 m: e: x3 a. j5.39.217.76TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. W8 `' e* B7 d
5個囚犯,分別按1-5號 在裝有100顆綠豆的麻袋抓綠豆,規定每人至少抓一顆,而抓得最多和最少的人將被處死,而且,他們之間不能交流,但在抓的時候,可以摸出剩下的豆子數。問他們中誰的存活幾率最大??tvb now,tvbnow,bttvb' I8 F, v3 ^  {6 E

5 g, A7 s& D( v. z. j0 _# V( k' Ftvb now,tvbnow,bttvb提示:
; _0 H) Z, u* q8 ~, @5 y5.39.217.761,他們都是很聰明的人;
  X& e9 c3 Q9 C3 R* D2,他們的原則是先求保命,再去多殺人;
. ^$ z% o" T. J2 G" }5 i% ztvb now,tvbnow,bttvb3,100顆不必都分完;! p/ P; @/ A6 u0 b' l( y5 P8 J
4,若有重復的情況,則也算最大或最小,一併處死;
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& ?; F2 b6 {# M0 z6 O6 A* N1 ?5.39.217.765 p) R$ F# c! q' ~( \0 n! i" e9 q/ [
答案晚點公佈
  `  o6 s% t. ^% Y+ ]) i; l! ~1 q, LTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。tvb now,tvbnow,bttvb% e* ^, K0 X1 g$ g

$ F7 J$ q3 U; ?" P3 u2 Etvb now,tvbnow,bttvb
5 U2 k: x9 [2 a4 [2 G7 K# i* [' \( U
$ u3 G* X8 A3 `2 I8 n" fTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5.39.217.76/ S+ b6 r9 L( }; r* h0 t4 B5 I7 j
5.39.217.769 `4 z- J& V3 o( e  D" _
答案:結果是只可能大家一起死。無論怎麼拿1號都是死的,所以怎麼樣他都得拖人下水,1號會拿20個,結果是前4個都拿20個,最後一個拿幾個都一樣,大家一起死。
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[ 本帖最後由 蘭昀 於 2007-3-7 05:11 PM 編輯 ]

err

no.2? cos he can counts how many no1 took from the bag....only a quick guess

sorry forgot explain

if no1 took 50, the bag left 50, then no 2 takes 25 the must be in between, if no1 took 30, bag the bag left 70, take 29...etc,
da answer is NO.5 coz he don't hv to do anything n da first 4 people is die already...................
Don't kow
they will all die becuz they will each get 20
真係好難
>:D< 開估啦 !
NO.1 ,NO3 AND NO4
有难度,慢慢想
why
好好想想!
I had a quick guess, is No.1.
- w) e( G: B; k( |Because what ever he or she taken, the next person will take what ever had taken with +1 or -1 to ensure they havn't got the same number. at the end, no1 will had the most likely middle number and without a same number. of coz he will need to pick a number from 3 to 19.
i don't know
看来我的智商确实比较低,乖乖的等答案吧! :'(
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