let the 12 balls be numbered 1,2,3,4,5,...,125.39.217.76& ?; `. P8 [- G
weight 1234 with 5678tvb now,tvbnow,bttvb; h$ P, s7 C7 x8 k9 g8 [
case 1
+ ?. h6 k" i/ d4 N8 m% `5.39.217.76if 1234>5678, then weight 125 with 678
! T% H. Z ~, I! u" F6 \0 ]if 125>678, then weight 1 with 2公仔箱論壇; e7 T. V7 r. I( R9 E) ^
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2tvb now,tvbnow,bttvb! ~8 J" S) ~4 e2 _' ~) [7 r
if 125=678, then weight 3 with 9
# S$ y3 \" b8 Y: R$ _! C公仔箱論壇if 3=9 it is 4, else it is 3' R2 ]2 a, Q S0 p3 D( n
if 125<678, then ewight 3 with 4公仔箱論壇! D' _( C. e7 v4 X
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
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! \4 a7 C; D6 b2 Q7 \9 `! q公仔箱論壇case 2
! T7 _% `. v2 F. P公仔箱論壇repeat above for 5678 instead of 1234 if 1234<5678
% J0 c! W3 N, ltvb now,tvbnow,bttvb
1 Q# ^* w9 Y+ t7 \! [8 S公仔箱論壇case 3
1 `( @) x9 y* W5 G0 Rtvb now,tvbnow,bttvb1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain
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' \; v+ ?& P, X( ?- o7 L公仔箱論壇[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
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太简单了吧？