put six on each side first5.39.217.76( U' F' F; d: T% ^
7 k1 l7 a% h6 H6 Q% S
from the heavier six, split it to three on each side
( O3 P* z( @7 W/ y8 ]4 V$ a6 k4 ^ u4 A3 K8 X2 g2 U
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |