put six on each side first
6 F' @5 E* s: \5 a$ m- ntvb now,tvbnow,bttvb$ G8 G3 L( ?+ P) F, h
from the heavier six, split it to three on each side5.39.217.76 ?4 A" s7 h, {
5.39.217.76; H0 j$ p$ k1 l; \6 D2 A
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |