let the 12 balls be numbered 1,2,3,4,5,...,12
. \6 Z; m2 r, uweight 1234 with 5678
4 E1 O1 ], _- vcase 15.39.217.767 ? Q4 o$ ^& O/ s
if 1234>5678, then weight 125 with 678
4 C U6 t0 X/ y/ R: o2 T' K: a8 o公仔箱論壇if 125>678, then weight 1 with 22 [# M$ Q O7 t7 U: V* X
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2tvb now,tvbnow,bttvb& v3 K. p7 w& F# z) j( x# u
if 125=678, then weight 3 with 9( E# t# x* l" s+ G
if 3=9 it is 4, else it is 3
N* ?: @# e; F! k) r6 N: l5.39.217.76if 125<678, then ewight 3 with 4; m1 X! q) Z; L, G. U
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
( P% |5 n+ s5 K" P公仔箱論壇
- C5 A9 e- g, @6 ~case 2
( G* c: Z; R6 G! \' x5 c8 f3 E4 v4 Xrepeat above for 5678 instead of 1234 if 1234<56785.39.217.76) M4 ]( T$ I- s
tvb now,tvbnow,bttvb* x( o( F9 G, i6 [; C. X
case 3
( d ]2 k. |* v z9 m+ |4 Dtvb now,tvbnow,bttvb1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain& u) r" X+ e5 {% H
/ Q! F8 e# h1 X0 H! ?
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
| 
太简单了吧？