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why
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let the 12 balls be numbered 1,2,3,4,5,...,12tvb now,tvbnow,bttvb, S" R% S: z0 K5 v# i
weight 1234 with 5678tvb now,tvbnow,bttvb0 k, B+ l: H8 ]) h# m$ E! U
case 1
% P* m! O- _6 MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if 1234>5678, then weight 125 with 678
3 ^( ~" N  I0 G2 \( |; u% Xtvb now,tvbnow,bttvbif 125>678, then weight 1 with 2  D8 [) Q' z9 o- [& S2 q% X6 p
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2  u7 d2 u, l9 g1 d; O7 {5 c$ G
if 125=678, then weight 3 with 9
( X& S) B7 M- m7 ?公仔箱論壇if 3=9 it is 4, else it is 3
0 [/ h' i) i, n( w* K& `1 Rif 125<678, then ewight 3 with 4
0 p# G+ I0 k: ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
3 V# f( M3 V% [0 K* {tvb now,tvbnow,bttvb公仔箱論壇  B$ k% e$ [2 s
case 2
( C& F1 ^. Z+ p0 ?" crepeat above for 5678 instead of 1234 if 1234<5678tvb now,tvbnow,bttvb6 q0 M% R8 R% v  s- a: N7 X

( C4 r8 c: o* {3 f2 T0 }case 3, J$ M/ W; U) q1 ]
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain
8 Q0 m/ v3 S2 J$ N, z5.39.217.76
% Y9 ^0 P( M$ |/ j; Z* btvb now,tvbnow,bttvb[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ]
thx
how?
the ball's weight is abnormal than other, not only heaver than other

回復第 1 帖由 MagicAndy 所發的帖子

好贴啊~~~
我都諗到.. 但唔知岩唔岩
实在想不出了
=.=
CC
太简单了吧?
cc
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