put six on each side firsttvb now,tvbnow,bttvb+ E6 I( H2 C) Z0 a) ?; O
$ y2 e, X3 u, M }tvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side
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then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |