put six on each side first, u( V# z9 C; M8 p$ @
# A, j) t" n: A0 x2 Qfrom the heavier six, split it to three on each sidetvb now,tvbnow,bttvb( c: F# h; _5 Q& h- r6 x
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then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |