put six on each side first5.39.217.766 Z5 q. r- t1 V$ ]% o( E
# m# r% k3 ?, i2 @6 E" hfrom the heavier six, split it to three on each side5.39.217.76( a. ?* `' |5 o$ A& m& k
1 S" t% s/ k% a4 V4 Gthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |