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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.76. w: P$ U- @8 V: g
共四堆
+ N3 g' Z+ r1 S, E. f: @5 D称两次得出异常的在那一堆,其轻重
3 T/ R6 h0 z1 ^+ q/ i8 }5.39.217.76在异常的那一堆中在称一次
: E4 |2 E, m2 C* [5.39.217.76就可以找到了
divde the 12 balls into 3 sets of 4.
4 n, h% y. J( u/ w) _TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.
8 `1 y- K/ Z3 q1 e" y" ]5.39.217.76if the 2 sets are equal, then you know the heavy one is in the third
( X  W% N; x/ W& v& E/ G$ _; mtvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set0 @' c! Z% R$ q# f9 F7 @. D8 l
then divide the 4 balls into 2.公仔箱論壇3 {* e1 {" R, V4 E7 ^  t' Y
weigh them
/ k6 o% a3 p$ s- Iand divide the heavier into 1
4 U. |% Z' x+ Y5 q) z( I: \公仔箱論壇and weight them.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 y: Q7 i0 ?# w1 u9 p
3 x weighing and get the ans.  
0 ~' X0 O6 f! K公仔箱論壇in less than 15 secs.
1. 6 aside and weight.  d: t, N( f' W. X! C& n9 e
2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb6 T1 o, N7 r) E- \) t' I
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.76* O/ z1 v2 J* x& ?* ?$ K
* B( u3 K* l% o+ I$ G- J% |% C/ J
but i have a question. 重量異常 can be heavier or lighter.... so......
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