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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb; h6 I$ h; ^) E2 e8 v$ z7 N5 z
共四堆5.39.217.767 k0 n, ^; a4 j: M' x
称两次得出异常的在那一堆,其轻重
7 }% _9 f. N7 }4 r2 A" g' n& b在异常的那一堆中在称一次
2 ?: K( y9 D" j# e  j% G/ y5.39.217.76就可以找到了
divde the 12 balls into 3 sets of 4.
2 u( Q! O- C6 jweight any 2 sets.
% B) w; x+ O$ o* ?if the 2 sets are equal, then you know the heavy one is in the third
* m; _6 _" L+ B7 g9 sif one of the 2 is heavier, then the heavy one is in that settvb now,tvbnow,bttvb" z, x' v$ }2 P7 K- t, I
then divide the 4 balls into 2.5.39.217.76/ M5 |. o( I% `/ e/ e, x% c
weigh them5.39.217.763 D9 X  H+ A& B# A$ H4 d  `4 i( s1 M
and divide the heavier into 1
- @! ?' I( E! B: @) n, c4 r公仔箱論壇and weight them.
& [# \  q) _) Q! B3 x weighing and get the ans.  公仔箱論壇" G* g: c, M8 a$ ?! ~% p
in less than 15 secs.
1. 6 aside and weight.8 q" w" h2 q: }7 {
2. heavier side from (1), 3 aside weight again.
& H4 R# g; j7 R& o, q6 }3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
/ S  |# s3 U2 k: `4 ?TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
* _5 m: q. V5 o. m) p# s/ ~tvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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