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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆) |' B; f+ ^& R2 l( k
共四堆
/ N) C# u" j* m% @. [0 }2 X% V) t称两次得出异常的在那一堆,其轻重公仔箱論壇1 a, @3 k, Y& ?) Z0 F
在异常的那一堆中在称一次
, [; v+ O8 V4 h: X  M就可以找到了
divde the 12 balls into 3 sets of 4.
9 N( y) R, I7 R% Uweight any 2 sets.* [0 M* V# {9 V5 R5 r1 N
if the 2 sets are equal, then you know the heavy one is in the third7 v/ k$ ~8 o( F9 u+ w
if one of the 2 is heavier, then the heavy one is in that set
5 y  X; K0 F. d# c' O" MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。then divide the 4 balls into 2.
$ M8 P1 Q5 G! S/ W5.39.217.76weigh them
3 n& g' G4 [0 M' fand divide the heavier into 1公仔箱論壇, k% d# O2 B3 h# Z6 d8 {9 ?( w9 Z
and weight them.
# N# \0 B$ y: }5 Y: ~6 @3 x weighing and get the ans.  $ c5 D4 Y6 V+ |6 ~& x; a% d8 K
in less than 15 secs.
1. 6 aside and weight.
) A9 V. ]& x* _5 C/ K4 F2. heavier side from (1), 3 aside weight again.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, r; D$ ]) V5 }4 l+ i0 F! U
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
. Y: m% y, R4 Q% Htvb now,tvbnow,bttvb5.39.217.76' |' G  _% x! b7 x1 v
but i have a question. 重量異常 can be heavier or lighter.... so......
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