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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb! j. L# U. A! F$ N5 C
共四堆
$ r9 v  o* ?1 f& k称两次得出异常的在那一堆,其轻重$ ]7 X; K' M1 I- r/ s, O
在异常的那一堆中在称一次
5 M5 Q4 G* P6 L: `! r+ CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。就可以找到了
divde the 12 balls into 3 sets of 4. 5.39.217.76, S; h4 R; r  _) D2 [0 |) D
weight any 2 sets.$ b) }3 y) P) T3 }, l! d
if the 2 sets are equal, then you know the heavy one is in the third
6 D' z7 U  I1 t5.39.217.76if one of the 2 is heavier, then the heavy one is in that set
$ T0 Y+ \: k  J( [then divide the 4 balls into 2.5.39.217.763 m6 B; i! t! K2 x0 k" y- u
weigh them2 U: `$ z5 x* L& d+ c' ~
and divide the heavier into 1# P1 H9 v. W* L$ @( d1 i
and weight them.
, K/ J: A- Z2 Q5 [, d* h; d9 M+ htvb now,tvbnow,bttvb3 x weighing and get the ans.  tvb now,tvbnow,bttvb! G' x8 O. a8 T2 |5 o
in less than 15 secs.
1. 6 aside and weight.
$ N, V- p- g8 I, A$ a公仔箱論壇2. heavier side from (1), 3 aside weight again.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ f4 [5 M. Y. J' _
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.76* s% @3 X2 Y: X/ Y6 T
tvb now,tvbnow,bttvb! m% }2 G1 _9 ^* n! l
but i have a question. 重量異常 can be heavier or lighter.... so......
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