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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆tvb now,tvbnow,bttvb% k3 j+ S$ U9 t/ a$ R3 R; {0 d8 R
共四堆
) \5 [5 s3 u$ Z# tTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。称两次得出异常的在那一堆,其轻重
5 H  [  j6 z8 y8 j, |tvb now,tvbnow,bttvb在异常的那一堆中在称一次5.39.217.763 v& L- E) j/ L4 {
就可以找到了
divde the 12 balls into 3 sets of 4.
/ O! l9 H7 a. ^% d) CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。weight any 2 sets.  o+ I( V9 W2 z) O/ s
if the 2 sets are equal, then you know the heavy one is in the third
- N( L4 T$ x1 f% i1 k0 n& C5.39.217.76if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇, ^: Q+ Y1 E- v6 d9 G7 o2 I4 J
then divide the 4 balls into 2.5.39.217.76$ t9 S3 D. g6 |, e3 X. [
weigh them
1 g0 K/ X7 j+ R; g0 E  L' K5.39.217.76and divide the heavier into 1tvb now,tvbnow,bttvb9 ~+ l* ~0 E6 e: I. @4 Q% }& E' A
and weight them.4 e( ?+ g  E# v5 U
3 x weighing and get the ans.  
: Z0 Z% Y" z- T& N/ g. {" ?& utvb now,tvbnow,bttvbin less than 15 secs.
1. 6 aside and weight.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 E0 b, t2 j! M7 F, ]0 O7 l: A
2. heavier side from (1), 3 aside weight again.
5 u) Q$ [; n9 F& M0 r. x6 b3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
! J2 c" v+ |$ `+ z7 w5.39.217.76tvb now,tvbnow,bttvb0 v1 {( M! l* e. G
but i have a question. 重量異常 can be heavier or lighter.... so......
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