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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆6 u3 }/ H+ d9 M# M6 L- i
共四堆TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) b+ O8 ~% `% ^& I( F7 D( F1 @
称两次得出异常的在那一堆,其轻重
* z6 l1 r/ [- q5.39.217.76在异常的那一堆中在称一次
; v* ]0 f  W& ~TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。就可以找到了
divde the 12 balls into 3 sets of 4.
9 L! Y# b  G  I. V5.39.217.76weight any 2 sets.
+ v* p3 y" ?* P# Mtvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
) X( I3 p7 x2 i) H9 ^3 iif one of the 2 is heavier, then the heavy one is in that set
* R8 u7 F3 W5 n2 Z$ a* d% g/ f! ]+ j5.39.217.76then divide the 4 balls into 2.
4 O2 w, S7 j8 U% h% ?5.39.217.76weigh them
: s  l& l" h9 Gand divide the heavier into 1
, G6 ]; h! E7 `+ u  t) w4 Iand weight them.
" h" _. s- a2 h1 n& |! L公仔箱論壇3 x weighing and get the ans.  
! V4 ^, x& l) c+ L! J9 q公仔箱論壇in less than 15 secs.
1. 6 aside and weight.5.39.217.762 _) n  `2 |! r7 Z, ?1 ?# v8 `
2. heavier side from (1), 3 aside weight again.
' v/ r, p. s2 i: J' t0 p- e3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. % H3 u: u+ v2 r: V& Z" s" u! P- @4 C) \
2 g# u2 o, l2 R! X4 ]; q5 j% s
but i have a question. 重量異常 can be heavier or lighter.... so......
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