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好難呀...
難...
好難呀....
ddd
好難喎
There is 12 balls.. divide them into piles of 4
% I. r4 Y/ x# ?! n( \0 _5.39.217.76so 3 groups for 4..name is A,B,C
# f5 I# d5 z6 m+ E! [  Mtvb now,tvbnow,bttvbcase 1:
8 E  T: F" M1 Ameasure A -- B : h% ^' y# v8 y5 G, N
A or B is heavier
( }! \" b( Z6 f& |3 ?tvb now,tvbnow,bttvbdivide that group into 2 by 25.39.217.76- x& ~4 o0 a+ W3 K' _% l: [% c* e5 @/ T) ?
then divide heavier group into 1 by 1
5 w* F  ]2 s$ _4 m% `. ^5.39.217.76tvb now,tvbnow,bttvb# W' s6 V: V$ e/ u
case 2:tvb now,tvbnow,bttvb* h) d' L5 p# F* T; b
A and B is the same.. therefore C has the heavier ball
9 m$ `; V  V, z0 ]tvb now,tvbnow,bttvbdivide C into 2 by 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ h1 O) Y5 [% U% i
then divide heavier group into 1 by 1..
5 V5 [3 f7 r3 T  Z* ~公仔箱論壇公仔箱論壇% l1 L( N! G& W
got it in 30 seconds.. not so hard -.-'
thx
i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.
0 L# s2 T9 A5 H6 P公仔箱論壇0 i4 J' t! h; ~: z' G
they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.
睇下先
do this is so boring...
  [( ?$ N3 u0 X8 F9 \5.39.217.76play game la~~~
[-X OK la^:)^ ^:)^
一知道有答案睇就唔想谂咁耐了
?
why?
多謝大大的分享
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