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好難呀...
難...
好難呀....
ddd
好難喎
There is 12 balls.. divide them into piles of 4公仔箱論壇: ~7 ?9 T& C* |8 ?0 E' G9 S& q
so 3 groups for 4..name is A,B,Ctvb now,tvbnow,bttvb) t' O; }9 X; V- E% V. e7 S
case 1:
$ U7 h0 j* a0 n" O公仔箱論壇measure A -- B 公仔箱論壇* Y( d1 G  u: w, J7 U% Y* F
A or B is heavier tvb now,tvbnow,bttvb5 R, T" q' Y+ a7 V' ]
divide that group into 2 by 25.39.217.76; G+ q2 I0 M& S& o+ R
then divide heavier group into 1 by 1tvb now,tvbnow,bttvb$ `7 J) i$ f& o* H3 @8 D& v$ V
) P% }5 s6 w$ c' x/ z+ G) A- r
case 2:tvb now,tvbnow,bttvb: k+ X- f0 W2 {1 p
A and B is the same.. therefore C has the heavier ball
- j; F7 \; o3 G2 `* t3 @divide C into 2 by 2
. j" r" p( I) p+ s, z7 j: [6 E" Ftvb now,tvbnow,bttvbthen divide heavier group into 1 by 1..9 s  R  \( g% a. g
5.39.217.76( [8 n) ~# O% x& E; r8 F7 y
got it in 30 seconds.. not so hard -.-'
thx
i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.
! B  l% B$ r4 S8 ~, a. }公仔箱論壇# ]" [3 @9 M3 Z' d. ?9 B& w# X
they separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.
睇下先
do this is so boring...
9 }5 k( A! F7 y8 X- O公仔箱論壇play game la~~~
[-X OK la^:)^ ^:)^
一知道有答案睇就唔想谂咁耐了
?
why?
多謝大大的分享
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