返回列表 回復 發帖
好難呀...
難...
好難呀....
ddd
好難喎
There is 12 balls.. divide them into piles of 4
' Q; A, {6 i/ h* G' R' jTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。so 3 groups for 4..name is A,B,C
5 B$ q4 O1 A2 y4 j, m6 d2 Ztvb now,tvbnow,bttvbcase 1:
, u' P1 X6 E) K1 K" }9 A, @" J" vmeasure A -- B
, U/ j* Q, t3 g! B: `% U' ]% Utvb now,tvbnow,bttvbA or B is heavier 3 f. [4 S6 c# `
divide that group into 2 by 2
: `- A! K; G* g) E: M5.39.217.76then divide heavier group into 1 by 1
% y/ h+ S4 s- o$ M5.39.217.761 |  b5 _7 ^& x2 S  \$ f
case 2:
7 |& |" Q! a3 l. R$ P( H公仔箱論壇A and B is the same.. therefore C has the heavier ball
+ r& n; `2 r' D6 |3 Z8 r3 Jdivide C into 2 by 2
( o0 f! \, c9 s& @then divide heavier group into 1 by 1..5.39.217.761 E) ]: m! k- y+ \
公仔箱論壇: a4 Y" I2 J: S7 V/ U
got it in 30 seconds.. not so hard -.-'
thx
i got it.... separate into 4 group 3(a)3(b)3(c)3(d), weight 2 of them(a,b), if it is the same, weigh b and c, if they are the same too... then the different ball must be in group d. if you weight different, you identify that group according to the different group. Also, we know the the different ball is heavier or lighter.
, I: B6 ?: J+ h" r. r" a$ {) ]; |
/ ]9 r+ \( I( Atvb now,tvbnow,bttvbthey separate into 3 group111, weight 2 of them. if they are the same, the extra ball will be the different ball. if they are different, the heavier/ lighter ball will be the different one according to the previous weight.
睇下先
do this is so boring...tvb now,tvbnow,bttvb  ~. w9 _% H5 w4 i' p
play game la~~~
[-X OK la^:)^ ^:)^
一知道有答案睇就唔想谂咁耐了
?
why?
多謝大大的分享
返回列表