joyce_c

cabuteh

em... how ar??

iShnaRngo

好难

kekelee

先6/6 得出一边重一边轻,然后3/3 分2组,因为异常的只有一个球,所以得出其中一组3/3是等重的.反之另一组是有异常的. 在正常的取一个出来,得出4个,然后2/2  1/1 出结果

boiminh

不知道

owen63

??????

triplenine

Anwser pls

mekl_2233

4 vs 4, two case => a)same or b)diff.
4 ^3 u) h; I2 V( E" u8 P( i1 D公仔箱論壇a)the not weighted 4 have the target, take 3 to weight with normal => same=the forth is target, diff. can let us know the target is heavy or light, weight two of those contain the target will let us know the answer  5.39.217.76$ m- n, f( f: t9 `# ~' o2 s0 N
b)diff. result will have light and heavy again 4vs 4, C vs D C=(3 normal + 1 heavy), D=(3 heavy + 1 light) => again 2 case same or diff., For diff. if C is heavier, than the target is that put in C, if D heavy, the 3 heavy can be weighted with 1 vs 1, heavy one is the target... For same, the target is in that 3 lighter ones, weight them 1 vs 1 will let u know the answer...

雄鹰横扫

太······容易了，第一次做就用左1分钟左右TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ u  w* M3 w0 |# ?( k. O! `' A" b4 C9 V9 ]7 Z
公仔箱論壇0 F+ _% N6 ?8 w% F) Mtvb now,tvbnow,bttvb- o5 ~+ A* {% l, E+ }
第一次称，两边6个，甘样肯定有一边会重D。跟住重D果6个分开两份每份3个称第二次。又系肯定有一边重D。剩低3个。抽其中两个称，如果重量相等，则没有被选中嘅球系最重的。如果重量不等，则重的那一边就是那个ball了

2006xg

很简单啊公仔箱論壇6 R9 c( Z2 |: P. @
12球分两组后，重的一边 两个一组分三组，同时放上两组，如果天平平衡说明在没称重的那两个球里，然后把那连个球一边一个。马上出来，三步！如果在开始放的两组里面，把重的一组拿下来，一边一个，及的答案，也是三步

HIHA5121

why= == == = = ==

zhangyining

算不出，看答案吧