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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次) U' w; Z. ^6 `1 U& y
将比较重的那份再平均分成两份成一次
5 [. F8 O1 W1 Q7 ?6 X) h( M公仔箱論壇剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4tvb now,tvbnow,bttvb+ R7 J- n! q6 Q2 O' C
if  (4v4)= same that means the rest of 4 is got more weight" d) |% j# D) X' v; a$ r
    then goto 2 - compare rest of(4)  - 2 with 2
% f$ b, e2 D) J, P" L2 E6 j+ b* C5.39.217.76           if (left side is more weight)tvb now,tvbnow,bttvb' B! N1 _3 k$ \( x, y, X* i
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
( R& @6 s# M' g! s公仔箱論壇          else ( right side is more weight)tvb now,tvbnow,bttvb+ V  q& \6 g& K/ \) {7 J
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer公仔箱論壇8 U) t1 B9 Q; T" _& C" u
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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