zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。/ t3 I5 q4 p$ Q( o' E
将比较重的那份再平均分成两份成一次7 p: l! D( @; ^, R
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4: o8 |4 f- V, K+ B# J
if  (4v4)= same that means the rest of 4 is got more weight4 K+ q% R/ y' E; `, o
    then goto 2 - compare rest of(4)  - 2 with 2 * u+ A+ ]- t* g" e
           if (left side is more weight)
2 E+ x$ ~1 D3 L7 ^; r; X5.39.217.76              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.766 m* @9 G5 N# ~" m7 E- h; V2 X
          else ( right side is more weight); C4 c1 Z' @2 @; a2 K1 e, @. v  \
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer公仔箱論壇; I. A9 i% Z( t) T1 A
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。