1 - compare 4 with 4
) m: f: a/ ~) \" G# [! }if (4v4)= same that means the rest of 4 is got more weight
# h2 |! p* k; F1 ], ]5.39.217.76 then goto 2 - compare rest of(4) - 2 with 2 1 _: h1 w( ~# ?. C/ j
if (left side is more weight)& c3 ~5 `! S# V* k; r+ P
then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
1 l5 y" ?8 \3 e6 z$ Atvb now,tvbnow,bttvb else ( right side is more weight)5.39.217.76& C! H7 k% w" q5 h* Z" X* o
then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5 R- W0 Y: E/ j2 s( G
else ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
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