zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
) N' U7 i6 M1 lTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。将比较重的那份再平均分成两份成一次公仔箱論壇: q+ c( }  P: g+ d8 S. r$ c( n
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
: v: L1 Y! b# l/ e2 ~3 u' p) Kif  (4v4)= same that means the rest of 4 is got more weight$ {: D9 Y) w3 d1 \+ C0 _, G
    then goto 2 - compare rest of(4)  - 2 with 2
/ L1 ]) m5 e! U; s! H           if (left side is more weight)
2 W0 M8 y/ c; }5.39.217.76              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
: A0 B7 y5 ]! y公仔箱論壇          else ( right side is more weight)
5 \; K$ T, V% v- s7 a5.39.217.76              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
1 a/ |# I: f8 K8 E( w  }8 ~8 `: r5.39.217.76else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。