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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次5.39.217.76* g# B" k( ~  [& r" k3 k+ P
将比较重的那份再平均分成两份成一次
3 |% _$ K/ ?. _, q4 W+ D5.39.217.76剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 47 n# H' Z" w! s" N- t. F
if  (4v4)= same that means the rest of 4 is got more weighttvb now,tvbnow,bttvb: \2 }0 W; I& ?8 M* V/ s8 a
    then goto 2 - compare rest of(4)  - 2 with 2 TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: ?! M2 c+ M/ H5 [, ~
           if (left side is more weight)
5 Y( c1 H$ y, {( t: }: l0 t3 M+ o公仔箱論壇              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
3 i; s; w& b" D. c$ r* N公仔箱論壇          else ( right side is more weight)
* \6 E( G# y: @! v- p5 ~: N              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
2 w4 W* b3 n1 {+ }: \# a, G  [else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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