zozozoo

直接看答案！

chungary919

i find one solution that is similar5 k- [- h: Q) u6 d5 z
but i can't specify the heavier one is abnormal or the lighter one is abnormal when the case that has only two balls left....
  y3 k9 ]! V8 k6 Jtvb now,tvbnow,bttvbmaybe there is a better one, let me see sin

chungary919

it is already good IQ if you can understand the answer......

bbbnd

pretty difficult... needa see answer

yind

!!!!!!!!!!!!!!!!!!!!!!!!!

jyllc999

444tvb now,tvbnow,bttvb& o7 d" C9 k2 Z& L
22tvb now,tvbnow,bttvb) v5 x0 g7 T5 u. K7 z( h2 K. M4 m
11

jimmy5943

thanks for share:onion14:

lam7780

is that really possible, i want to know

cruzi

interesting ...

chlOe~~x

.... thx for sharing !

paddyleejun

ddddd

i761120

actually this question always have someone asked, the calculation is very complicated, should give a no. of each ball, and first weight it in 6-6, and .... forgot...

kelvinmok85

how oh???

counterpain

Let me see the answer