let the 12 balls be numbered 1,2,3,4,5,...,12
+ C; `3 A r- D Z8 t1 y5.39.217.76weight 1234 with 5678
" H/ n: Q/ k/ `2 V& [case 15.39.217.769 f, m& y. C' V' P4 m# f0 I+ M
if 1234>5678, then weight 125 with 6785.39.217.76, s, @: Z7 F# F- |7 j
if 125>678, then weight 1 with 2" Q1 Z' D# O7 ^" r- E x, A& U
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
9 o; M# z0 Y( F) ^$ Pif 125=678, then weight 3 with 9tvb now,tvbnow,bttvb4 Z2 ^% o& N7 X8 ? }
if 3=9 it is 4, else it is 3
. ?5 J4 j( b" T9 T/ fif 125<678, then ewight 3 with 45 x7 W0 p! g# m* k4 g* S6 y
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 45.39.217.76+ ?+ i J3 j4 G" x6 M! {6 y( E1 w
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case 2# R" [3 H/ }& E7 u5 m# Q6 o9 f" n
repeat above for 5678 instead of 1234 if 1234<5678
- N: ?! a2 r. k
' M1 ^" N3 J; i8 ytvb now,tvbnow,bttvbcase 3% j4 E& s0 q- K( W* |5 A: O, r
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain
' v/ f A/ o: E; j( L公仔箱論壇* R3 S6 o. k5 |& d: l
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
| 
太简单了吧？