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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆' R# d% E4 N# w2 B' g
共四堆
/ }5 u5 f0 R3 z1 I: dtvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重
' L5 _7 d2 c) o/ l- s6 xTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。在异常的那一堆中在称一次
) o& ^3 _0 @. G就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb% U$ I7 n+ e( O1 n! n7 E2 l/ u
weight any 2 sets.tvb now,tvbnow,bttvb- D9 z# r- q& X4 f: B% m
if the 2 sets are equal, then you know the heavy one is in the thirdTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 V  R0 T3 D' m, w/ Z( I+ ~
if one of the 2 is heavier, then the heavy one is in that set
8 e) S$ [2 _1 B: y! F/ O公仔箱論壇then divide the 4 balls into 2.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。( ]" u3 w' D/ E  e& g  v# a! O
weigh them
$ u/ a7 `& I4 d! L& a. W- Utvb now,tvbnow,bttvband divide the heavier into 1
: @  C( Z' n6 o. i; f$ D4 u5 R' Q- zTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and weight them.
( h; c4 p/ w  J/ u4 C9 ]3 x weighing and get the ans.  
" ^* I5 r+ A4 U6 ]: f; oin less than 15 secs.
1. 6 aside and weight.5.39.217.76" B( v: o. q4 ^# ^) C- G) F
2. heavier side from (1), 3 aside weight again.
5 Z0 a9 s5 _$ d. g- K# jtvb now,tvbnow,bttvb3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 4 b( P/ o' C; [9 R2 D8 P. t

: J, g" w9 {" l, D# r$ utvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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