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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆- m  J( O: c$ K% m" t
共四堆
, t, P& t! ^7 _5 Q( i6 i称两次得出异常的在那一堆,其轻重5.39.217.762 @7 s1 d( \3 L. T, R
在异常的那一堆中在称一次TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。5 z* p- ], I' z
就可以找到了
divde the 12 balls into 3 sets of 4.
$ W% F2 o0 y4 z$ ^* W& }公仔箱論壇weight any 2 sets.& L! u. v  Y4 o
if the 2 sets are equal, then you know the heavy one is in the third公仔箱論壇5 i0 F) k& y0 S5 ~% ~: T+ d
if one of the 2 is heavier, then the heavy one is in that set公仔箱論壇5 m" d6 A. O7 |# i" s
then divide the 4 balls into 2.4 k$ p7 m2 ^9 l2 X+ h$ W) C1 X
weigh them
2 \" I6 E2 p: O; s" Mand divide the heavier into 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。) V$ Y/ o7 f% I$ k1 G
and weight them.( t- Z9 z3 Z( U
3 x weighing and get the ans.  公仔箱論壇8 @3 q. `8 Z+ e7 d* L
in less than 15 secs.
1. 6 aside and weight." c! P+ j9 ?7 |  }2 F
2. heavier side from (1), 3 aside weight again.
% V, ~  X7 k" p0 }9 z- n5 m$ u1 i公仔箱論壇3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
8 m. f9 T3 p8 y+ c: _
. A7 V7 S# ?& O+ w( ]& htvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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