1 - compare 4 with 4) N7 t: n- T ?# G+ A
if (4v4)= same that means the rest of 4 is got more weight: ]$ R6 e5 ~3 H" j( C- F; l$ K
then goto 2 - compare rest of(4) - 2 with 2 5.39.217.76: u8 w/ y4 X6 v0 y- S
if (left side is more weight)( |+ ?, B! s7 Y3 t: P6 i
then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb0 b# {9 c$ \( ~! n; p$ [: z
else ( right side is more weight)5.39.217.76/ w. H) `) {8 m
then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
8 Z2 @6 R* J! n, Felse ( the left 4) then compare with above , or right 4 also can compare above method... |
發表於 2010-9-21 10:33 PM
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