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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
6 a! Z' c: Q* K9 U公仔箱論壇将比较重的那份再平均分成两份成一次tvb now,tvbnow,bttvb( [% z; j5 F/ }# n8 b: a8 j
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
1 v% r0 f2 ]! I) D8 a+ mif  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇. n2 V) w9 x8 O% j+ P( `
    then goto 2 - compare rest of(4)  - 2 with 2
" [2 o# m' P! L- ^, E  G3 U公仔箱論壇           if (left side is more weight)5.39.217.767 B( R/ @+ Y1 o3 O, p
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer5.39.217.76" K+ h, }3 V% R, {- M+ A5 c
          else ( right side is more weight)tvb now,tvbnow,bttvb- ?# u% F9 X# H( _( i8 A! d
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
: D* q; F( H' @3 P* n& o& Gelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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