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第2的....直覺告訴我
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友華
我已經想很久了TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. L% w/ _. ~- D
實在太難0 ^  u: d' ^/ B+ C$ T' C
只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
3 u4 ~3 n/ V3 Q+ s9 ~! wtvb now,tvbnow,bttvbassume number 1, 2, 3 and 4, pick number a, b, c and d.7 ]4 k. ?/ Q; n, w
number 4 knows how many left in the bag which is 100-a-b-c5.39.217.766 ~; }  U0 P, S+ Z
take the average of (100-a-b-c)
% B9 F. ?& Q5 x* Uthen number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
) r6 m8 y8 w' s' C5.39.217.76and number 4 can squeeze himself into the average and what number 5 picks.( W, K8 P% R' `0 J8 v
so number 4 will have the best chance.
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i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!
4 O' g5 P( L7 B) L$ }TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!1 y) n: J; `+ b
TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。  e0 p, A8 T3 j) h
如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
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8 o. v5 }, X! y, x             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18.
! ^) U0 Y! ?) X& WSo they will all die !!                                                      5.39.217.76$ I3 X9 h* l3 d; g9 k

  w) X$ O% M, s( P$ I公仔箱論壇1 ^0 G/ u; R4 K! c

1 `& P6 O" }! T, Z5 E# N9 {tvb now,tvbnow,bttvb5 y* k6 b) |" O

0 M7 y  T2 V; ?: K; F5.39.217.76Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
; j0 N6 i# _, ^9 E$ F+ v5.39.217.762 |; h: ~& ~. A* ?8 v5 s
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
0 r+ Q( e- Q- n2 q8 s7 vtvb now,tvbnow,bttvb. A8 {2 C9 i, n! \0 V5 l5 y" G+ V
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.公仔箱論壇. e4 y0 B4 Y* H/ [$ l% b7 ~

$ q* t1 P# F* q  P3 q5.39.217.76#3 did the obvious choice 40 divided by 2 =20, so he picked 20! y& q- d0 Z' p/ s+ T
5.39.217.76( E2 a6 ?5 y8 Y# M
#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.公仔箱論壇$ b5 ~( s: a: V/ Y

5 g% [* |/ I( r* g9 X; t8 @& Q$ _9 L' t5.39.217.76#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。9 W. F: f6 q; K" D6 @' p6 U
公仔箱論壇7 h8 U2 j* w7 I) V5 E% V$ }& M
Ended all have the same number and all died.
我猜NO4,7 K6 a+ p( Q- e/ F
因為他可以取前面三位豆子的平均數,tvb now,tvbnow,bttvb1 g* b8 q" V3 E6 f" K1 C
也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
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$ ~* j7 j2 b2 T) B2 W5.39.217.76[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,公仔箱論壇- k1 k5 u: W  P$ M2 L

# l/ `6 H2 Z- l) w* t9 \. u5.39.217.76答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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