The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。* m. }" w5 y4 F4 h ^ b4 f, B* x
5.39.217.763 Z! l9 \) P2 v; K, ]
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.
1 F9 f" I5 q% w' W4 _tvb now,tvbnow,bttvb; c5 r. r e1 q. r, U
Now #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。7 c" d/ D' l6 h( H2 a
$ k0 t, {+ o' T% R4 W% MTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#3 did the obvious choice 40 divided by 2 =20, so he picked 20
( _1 I. ]$ m& d; v! l. ]# v) Ptvb now,tvbnow,bttvb
8 `. `3 w$ {9 d) _, _, h/ `. ETVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
1 x, |# A& r/ C5.39.217.76公仔箱論壇7 X# j* |- ~4 T9 e0 I" P. w
#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
n+ k, m* ~7 v7 w5.39.217.76
# L3 E& O! t: I$ m公仔箱論壇Ended all have the same number and all died. |
發表於 2006-12-9 12:41 AM
| 
5.39.217.76* w; F0 i: ~% u4 p
