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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
% ]) E) y3 v& M' n公仔箱論壇1st u divide the ball into two group (i group 6 ball)5.39.217.76+ j/ w1 }/ T% s+ d8 x; i% Q
then 称 them c which side is the heavy 5.39.217.76! ?* i0 T9 L  c& t- t9 e! J$ M
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 5.39.217.769 R, t6 u1 a* ^3 D0 M- P0 U* V
if not balance take the heavy and then 1 p) N1 i7 s+ C% }; F0 m
take the heavy group divided into 2 group i group contain 1 ball than 称 it tvb now,tvbnow,bttvb- T6 ~/ f1 o7 b$ l; [6 k
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
8 ^7 B4 b4 j/ @; Z5.39.217.76(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
1 J- a9 s& p( l( a) T& ~公仔箱論壇然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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