hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
* f$ J1 R! r) ~% C: W: ~1st u divide the ball into two group (i group 6 ball)
. I2 y- }( b2 k4 B0 E# Zthen 称 them c which side is the heavy 5.39.217.76' l! V4 ^3 S8 J' b  e, D- a
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇0 i" `0 Y7 r: Z# M# ?# o
if not balance take the heavy and then tvb now,tvbnow,bttvb2 {; a. f4 X3 X4 e( d
take the heavy group divided into 2 group i group contain 1 ball than 称 it 公仔箱論壇3 p1 |7 r; @1 a2 X  E' Z# C
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
$ L, q8 r" s1 G; Z5.39.217.76（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边% }) E$ b3 ]- A4 K. E* u" d
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me