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[IQ題] 一道真正難倒億人的智力題

一道真正難倒億人的智力題tvb now,tvbnow,bttvb* d, G6 K' E: E$ V, Y+ J! o2 F; \: n' I
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( _0 m! T& F# p  Q6 d" ?% O; _5個囚犯,分別按1-5號 在裝有100顆綠豆的麻袋抓綠豆,規定每人至少抓一顆,而抓得最多和最少的人將被處死,而且,他們之間不能交流,但在抓的時候,可以摸出剩下的豆子數。問他們中誰的存活幾率最大??公仔箱論壇2 i  w: i4 Z* i7 [* J
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提示:
% ?; n7 C9 w) A3 U) z) q/ |1,他們都是很聰明的人;5.39.217.763 s7 L1 S$ W& u
2,他們的原則是先求保命,再去多殺人;公仔箱論壇" v9 Q3 H# |* i5 @* w
3,100顆不必都分完;tvb now,tvbnow,bttvb% G! D1 p; f! d. |' P8 p% w+ r
4,若有重復的情況,則也算最大或最小,一併處死;5.39.217.76: M+ r) N' r: t8 l+ _; t% `
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" c' \. b( o7 M  d1 V) \& Otvb now,tvbnow,bttvb答案晚點公佈5.39.217.769 r: F# _3 D7 l, T5 m, R" {7 J

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% t* Z2 Z/ P- s0 z' L( x9 `* b公仔箱論壇5.39.217.765 x5 K  G* `8 F- _# k# R
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. ~- [$ D5 ]( u7 x5.39.217.76
6 x1 p. L4 g& n; [1 ~答案:結果是只可能大家一起死。無論怎麼拿1號都是死的,所以怎麼樣他都得拖人下水,1號會拿20個,結果是前4個都拿20個,最後一個拿幾個都一樣,大家一起死。
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3 q$ G* Y  ^  O6 o公仔箱論壇[ 本帖最後由 蘭昀 於 2007-3-7 05:11 PM 編輯 ]

err

no.2? cos he can counts how many no1 took from the bag....only a quick guess

sorry forgot explain

if no1 took 50, the bag left 50, then no 2 takes 25 the must be in between, if no1 took 30, bag the bag left 70, take 29...etc,
da answer is NO.5 coz he don't hv to do anything n da first 4 people is die already...................
Don't kow
they will all die becuz they will each get 20
真係好難
>:D< 開估啦 !
NO.1 ,NO3 AND NO4
有难度,慢慢想
why
好好想想!
I had a quick guess, is No.1.
1 T, F0 y) Q0 U. h0 N6 H0 E5.39.217.76Because what ever he or she taken, the next person will take what ever had taken with +1 or -1 to ensure they havn't got the same number. at the end, no1 will had the most likely middle number and without a same number. of coz he will need to pick a number from 3 to 19.
i don't know
看来我的智商确实比较低,乖乖的等答案吧! :'(
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