put six on each side first$ ?- K- ~0 D0 A7 X, W$ c
7 e7 o, u4 n: R8 Gfrom the heavier six, split it to three on each side
; L F/ f* Q/ ], k1 Y/ n) P: S/ ^5.39.217.765.39.217.76; M' u3 U, J4 E% n* A
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |