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let the 12 balls be numbered 1,2,3,4,5,...,12TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。' I0 B1 ^/ }7 D  V
weight 1234 with 5678
( I; s" f5 b* q" T; ^4 X# B! _tvb now,tvbnow,bttvbcase 1( k$ y& G$ s' q; T
if 1234>5678, then weight 125 with 678
7 K' c2 y  c. [+ U. U" U" ~5.39.217.76if 125>678, then weight 1 with 2% _8 s0 e4 ?% a+ Q' v! E2 T
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
, O8 H# d+ h8 |5 c( `tvb now,tvbnow,bttvbif 125=678, then weight 3 with 94 s7 A* ^$ e! p8 Y+ K9 p
if 3=9 it is 4, else it is 3
( a. \7 ?5 ]9 U( N2 ?- i% e5.39.217.76if 125<678, then ewight 3 with 4tvb now,tvbnow,bttvb& c$ F. I0 N) O& G% O( h' l0 N
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4* o' ~" ^% n  m. w# f( o" @: L
tvb now,tvbnow,bttvb2 z- i5 J$ _+ O* }1 v. J
case 2tvb now,tvbnow,bttvb$ K+ j5 p( L& v: o$ W- U
repeat above for 5678 instead of 1234 if 1234<5678
7 m3 \( s* b8 g/ f& H- W
" ~/ j- ^2 d9 G2 h! {' E5.39.217.76case 3
- N. T5 W: J8 ^2 r9 ?% a  ?1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain
6 }& r& V  F' R' X/ d2 S" U3 R/ mtvb now,tvbnow,bttvb# V3 b8 A: s& w7 m
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ]
thx
how?
the ball's weight is abnormal than other, not only heaver than other

回復第 1 帖由 MagicAndy 所發的帖子

好贴啊~~~
我都諗到.. 但唔知岩唔岩
实在想不出了
=.=
CC
太简单了吧?
cc
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