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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆8 X2 K1 s7 K4 _
共四堆
' \  T% Z# e5 A8 M3 i) G. Ktvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 I8 a# U* x% k# F" H- Y
在异常的那一堆中在称一次
- J+ B9 d" @: ^7 `公仔箱論壇就可以找到了
divde the 12 balls into 3 sets of 4.
# e0 ^9 d- C( g1 ktvb now,tvbnow,bttvbweight any 2 sets.
) k5 |; a% N# H" M2 H2 fif the 2 sets are equal, then you know the heavy one is in the third
8 A7 }! e; M7 O$ S/ _: s& ^# E& Q4 _公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set) r4 {& q; m8 B% p
then divide the 4 balls into 2.
) Z6 Q7 F- ]9 K- F* g: h1 P) d& U2 ?weigh themTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 I: d& H- w- m  |; c, z
and divide the heavier into 1( e/ N+ Z- U; o: m) g- k
and weight them.
( Z" P" G6 o0 f5 s' [' l% t( y3 u5.39.217.763 x weighing and get the ans.  0 M* B: ?% m/ {9 T2 J! q
in less than 15 secs.
1. 6 aside and weight.
6 p1 j! F( E! \2 B  N) _6 l5.39.217.762. heavier side from (1), 3 aside weight again.# o6 M3 v1 z4 s1 D0 ^: o4 s9 v
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
0 E0 L* c  e7 Y! q% ?# [5.39.217.76
/ k2 Y1 W) g( |$ b2 B1 @! n5.39.217.76but i have a question. 重量異常 can be heavier or lighter.... so......
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