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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.76# J& m1 ~" n, N/ J' G: |( d1 i6 H
共四堆- ?: p5 S' E  N6 ?9 t1 g% [4 x; z
称两次得出异常的在那一堆,其轻重$ c/ o/ s+ E8 c' S4 F, F
在异常的那一堆中在称一次
9 y' j8 [/ g! Z1 b4 _/ O8 _tvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。0 H2 V8 n/ r2 k
weight any 2 sets.4 P* e: b3 e# F( Y$ ]2 b9 a
if the 2 sets are equal, then you know the heavy one is in the thirdtvb now,tvbnow,bttvb/ @- R! k( D) N/ f- k
if one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。8 V* J- n- [, M& R1 h# b0 e
then divide the 4 balls into 2.
" j9 q1 w9 G% J4 _' o5.39.217.76weigh them公仔箱論壇: |2 z/ l* ?$ s4 q2 w$ ~$ E: e) _
and divide the heavier into 1
1 Q; ~7 o: M) K8 b# b$ p$ i+ W, pand weight them.
6 u; V- D  ^$ Q" w6 J: F5.39.217.763 x weighing and get the ans.  
" A* `% m5 ?8 d) ^5.39.217.76in less than 15 secs.
1. 6 aside and weight.
4 u+ i3 u9 I2 E: W公仔箱論壇2. heavier side from (1), 3 aside weight again.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. _* n" {, X0 q$ \% A
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 4 v7 V* u9 r5 s5 R* O9 s
5.39.217.768 V0 N" t  l# m, c) t$ q  m
but i have a question. 重量異常 can be heavier or lighter.... so......
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