zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次公仔箱論壇4 _4 _7 U: o* d+ d7 Z) b" ~( x
将比较重的那份再平均分成两份成一次
% j6 o3 `: Q0 q- L$ c' R; S剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
. S! m  R/ k  q3 Itvb now,tvbnow,bttvbif  (4v4)= same that means the rest of 4 is got more weight5.39.217.768 _7 g; d- o/ X
    then goto 2 - compare rest of(4)  - 2 with 2
+ l# J# \" i. b# @% W           if (left side is more weight)) \$ z$ P6 }, t- y
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
" I4 h" \* m. G. N9 G公仔箱論壇          else ( right side is more weight)6 {% N* c9 o0 G) Q2 L7 g& m5 b
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer2 k+ U' p( m! G% R! |
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。