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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次公仔箱論壇3 S4 q' w/ x3 [
将比较重的那份再平均分成两份成一次tvb now,tvbnow,bttvb3 d( z! e5 o) D
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 45.39.217.76" C/ u) f  Q1 R" Y; T+ T
if  (4v4)= same that means the rest of 4 is got more weight
1 y8 e. g5 m2 ~1 C4 Z" ~TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。    then goto 2 - compare rest of(4)  - 2 with 2
, y8 a) s/ [/ Y$ `) L           if (left side is more weight)
/ W) x$ k1 K* v5.39.217.76              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
: x! v3 F3 p7 U7 z% r          else ( right side is more weight)
" ~- w" S9 e: s4 H/ ]              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer& E( a. o& W/ Y) L, x
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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