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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次6 C; ~9 `; i1 K/ d8 }- r* D
将比较重的那份再平均分成两份成一次, T! F. Z2 M/ w6 B8 B2 x( f
剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
9 ]# E: B! M- s8 r" m/ f  W9 i5.39.217.76if  (4v4)= same that means the rest of 4 is got more weight# x: O" Y; W. ?' p5 |/ N2 F0 D0 Z
    then goto 2 - compare rest of(4)  - 2 with 2 5.39.217.761 y- f3 R0 r9 G+ }
           if (left side is more weight)
# F7 t, p# c) |7 R2 b0 O+ d& ]+ |tvb now,tvbnow,bttvb              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
( H) _; F- b; w4 @公仔箱論壇          else ( right side is more weight)
8 R6 ]) \+ ]' V% \              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
1 Y# D- @0 ]/ Y7 eelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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