take out 10 balls and 5 in each side
# [9 Z+ v( T* H3 c: a2 p9 n; yif both side balance mean the other 2 balls one of them must be the heavy one then just take them to weight will find out which one is heavier.
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if the heavy ball is inside the 10 balls, take out 4 balls from the heavier side which had 5 balls to weight 2 balls in each side.
6 e0 M5 L, T7 s7 a5 U5.39.217.76if both side balance, which mean the one left is heavy one if not, just take the heavier side to weight will find out which one is the heaviest one.
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used less then 1 min to find out the answer.... |
發表於 2007-12-31 05:47 AM
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發表於 2008-1-1 08:48 AM
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