hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^; s) u1 t/ A; ^6 }9 q0 s
1st u divide the ball into two group (i group 6 ball)公仔箱論壇! d6 r& L# V+ a( ~: t
then 称 them c which side is the heavy
0 M7 K* {, @- r2 W0 o1 Kthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
0 B- z7 E/ m- Q# G5 }& R( l公仔箱論壇if not balance take the heavy and then
7 [( |) X& l$ w# q" ]take the heavy group divided into 2 group i group contain 1 ball than 称 it
- D! S) z- _; {1 D, n# Dtvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5.39.217.769 o' |0 \& u1 h) t/ |
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边5.39.217.76% ^5 j1 S8 Q% I: @
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me