hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^+ _* i% U1 e- s
1st u divide the ball into two group (i group 6 ball)
' Z5 x: |; Z& ~公仔箱論壇then 称 them c which side is the heavy 5.39.217.76! c$ c) I* G: n3 s! [
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group & {( R0 C; {( [1 W3 V3 B" T
if not balance take the heavy and then
1 Y+ q1 Y8 o4 q- c% J0 L; Ctvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
+ @' m- O: p4 w- C公仔箱論壇than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: & j% }% m9 h9 k! H5 k
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边4 X* ]3 W2 S8 O, W, q3 e
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me