That is a very simple mathematics question.; S: S) Z& y/ Z) M+ y
Let x = Male, y = Female, z = Child
! D1 @5 V& V" w1 R3 f& S# Ktvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
# T) b1 ?( q& P4 E4 L公仔箱論壇x + y + z = 100 Formula 2
" m% U5 s3 `3 z$ R' P4 W) CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.764 |$ y! s9 z+ {- f: R3 G) E9 X
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 45.39.217.766 g3 u2 p/ n' g1 k
Formula 4 can change into 11x + 5y = 100 Formula 5
9 A3 v& z$ e/ }tvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
1 x4 E8 y& _# \ K9 Z) s' {- WAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
2 [7 Z; O. o% K3 s! P( J# m+ z2 wEventually, the answer is 20 female and 80 children and no male. |