That is a very simple mathematics question.公仔箱論壇) K2 E8 @0 H# L6 a
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb7 }- \' d% ~( P8 c
6x + 3y + z/2 = 100 Formula 1
; _) W5 d: U- ux + y + z = 100 Formula 2, Q% B+ j- J: z$ n. r" D# r; B+ ~( n2 O
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
5 N1 v& ^5 \4 l* k8 c公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
$ G3 n; a& H4 m$ Y5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 5/ F4 Y0 T/ e& X: q" W! d
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇5 W$ [( d/ ^1 @; v" C& k
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ n0 S8 i- s3 A+ f" gEventually, the answer is 20 female and 80 children and no male. |