That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。 q3 H1 p- O7 H' Z
Let x = Male, y = Female, z = Child
6 |+ [* o4 K5 i& p* C9 T( |1 o: [6x + 3y + z/2 = 100 Formula 1
! k# v7 U- u( l; }' U2 Vtvb now,tvbnow,bttvbx + y + z = 100 Formula 2
. D A+ L' w: i# b) YSimplify Formula 2 into z, we get z = 100 - x - y Formula 3: ^) G3 Y/ E; U \2 e' Y. J% K
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
+ ]# k" p. V8 ^3 [! e) ytvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5
% Z, U8 ]; ^; @( fIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.- A1 O% q( K/ L
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇' y, ?: ^3 b% P, u% }, e. s$ q- a
Eventually, the answer is 20 female and 80 children and no male. |