That is a very simple mathematics question.
' X. Q' l2 p ftvb now,tvbnow,bttvbLet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb6 I! E! f, h0 y+ o2 a, K
6x + 3y + z/2 = 100 Formula 13 Q1 `7 [( `: Z# b0 R) i9 ~
x + y + z = 100 Formula 24 n4 t0 G m8 A5 G6 D
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.76- V) B+ k- u6 X1 {- `- [
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 44 ^9 U/ } s! s/ s" u2 k# k- J
Formula 4 can change into 11x + 5y = 100 Formula 5
; W* F+ k+ S9 b- g1 y, a/ I5 ~# ttvb now,tvbnow,bttvbIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.. @' z0 P% O+ b5 e) O8 T! k
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
9 x7 s! m) Y w: p; ?3 u1 M公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |