That is a very simple mathematics question.. V5 U1 W1 [/ ~" F# z
Let x = Male, y = Female, z = Child
. l% P, ^/ k$ Y$ w) [! j/ vtvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
* _+ s; ]4 v: xtvb now,tvbnow,bttvbx + y + z = 100 Formula 25.39.217.76/ Y, i0 F2 m3 c0 a" L; {, C L
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
% w, d' T F( b" C公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
- V" w# ~" {8 G! ktvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5, G( E. a' C% T& u0 k2 `6 }
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
2 B# O8 c/ M& d1 C% ~# K5.39.217.76And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.76& B+ M" q- H# z( A- E7 F. m: g- }
Eventually, the answer is 20 female and 80 children and no male. |