That is a very simple mathematics question.
0 I$ g- q; A8 N; ^2 tLet x = Male, y = Female, z = Child
. @) g- i6 a" J) `3 ~6x + 3y + z/2 = 100 Formula 1
% V: _6 M$ z9 _! L, Z# G7 ~$ tTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。x + y + z = 100 Formula 23 I$ `+ M( M: I2 F' _6 \# h; n5 H
Simplify Formula 2 into z, we get z = 100 - x - y Formula 31 w0 _3 f q. M
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
3 K$ x9 x6 S4 g {4 W. h9 ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 55.39.217.768 V* q1 q1 d9 W. y' w6 \9 P7 r: B
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
# y9 p3 s, E' h! p. Z; h8 n* n公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
- ]% o* i$ V. x+ y, M! j公仔箱論壇Eventually, the answer is 20 female and 80 children and no male. |