That is a very simple mathematics question.
/ x7 n+ r5 p$ `" p$ Qtvb now,tvbnow,bttvbLet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb; A/ a u. U# x+ q! E8 a* ?
6x + 3y + z/2 = 100 Formula 1
% S! B* K c c$ q4 D, p" yTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。x + y + z = 100 Formula 28 `% w8 Q4 ^ d7 v0 H
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
" i* T, T6 T ~, G/ J3 v; \Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb, U& s& E: T) k9 v( t% I3 J
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb! x3 ?& q% r$ [/ G( A
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want." m$ b3 e4 A# @& Y1 J2 @
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. ]3 d- X$ V$ v2 U! u/ }
Eventually, the answer is 20 female and 80 children and no male. |