That is a very simple mathematics question.
: I% }9 K( e' N' ? N4 ELet x = Male, y = Female, z = Child公仔箱論壇 u! _# R, Q; L. y" r2 t" Z+ q9 G: n
6x + 3y + z/2 = 100 Formula 1
8 d" X8 B' o |7 E) z. t5.39.217.76x + y + z = 100 Formula 2
. @+ Q& p$ B( j5 o5 S2 d) V+ kSimplify Formula 2 into z, we get z = 100 - x - y Formula 3+ V( ^/ r) w; `4 t8 J* E4 k" i
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。. }* o5 L( _7 h/ K# |/ V
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb0 @7 ~% L5 p& a2 y5 Q7 J
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76( ~5 c6 F6 f9 Q& E1 s$ N% g1 L
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
! D: U8 Z& Z! T6 e* iEventually, the answer is 20 female and 80 children and no male. |