That is a very simple mathematics question.
5 l& C3 m+ C! O$ w. R6 b# P公仔箱論壇Let x = Male, y = Female, z = Child5.39.217.762 n/ S5 @; {' S+ O
6x + 3y + z/2 = 100 Formula 1, V5 s( g' ^6 B6 L
x + y + z = 100 Formula 2* l: `- C1 t/ L/ V: W* n; J5 B: v
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。, m8 W: M* J1 t, Z( B& L7 K; A2 {
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
# i) L5 Z* f$ {# wtvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ D2 W# c+ h5 k. Z
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
2 M& x% K& R( p6 [/ O7 PAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
& g- N7 U5 S! G: S6 [' G9 Etvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |