That is a very simple mathematics question.5.39.217.76: Q; K; w9 f6 i7 ^0 V3 S8 I
Let x = Male, y = Female, z = Child
* }+ t3 W( k2 B8 j. Z公仔箱論壇6x + 3y + z/2 = 100 Formula 1tvb now,tvbnow,bttvb; i2 @. R' ?: X5 Y: v& I- s
x + y + z = 100 Formula 2
. x7 W. l' p" [; E6 E% C# }: V公仔箱論壇Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。2 u) b8 a9 V- o% I, f+ u- Y' c
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4- D# [% a4 S' U* a0 f) ~
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb% Q! Y0 x n9 [; A' B7 Y9 n. R
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
9 Q- B# ?- H, ]$ N% ^; z4 mAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.5.39.217.760 L- c6 p9 } D1 j
Eventually, the answer is 20 female and 80 children and no male. |