That is a very simple mathematics question.
& Z, d @. `3 |2 }8 r6 S+ stvb now,tvbnow,bttvbLet x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6 F( i5 B5 p- r: W9 { ?- K* w( W$ O
6x + 3y + z/2 = 100 Formula 1
) s3 W4 ?( T; |& }# f: Lx + y + z = 100 Formula 2tvb now,tvbnow,bttvb, i6 ^7 t0 g1 v) E0 g
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
3 l1 B) o" Q$ r) LSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
( X8 @7 c4 {( m1 ^Formula 4 can change into 11x + 5y = 100 Formula 5TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3 [# t+ t) f; g; u1 c+ C
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
" z+ h) q* {% Q0 L T1 Atvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb7 }+ A* J9 e/ t9 Z- s
Eventually, the answer is 20 female and 80 children and no male. |