That is a very simple mathematics question.
0 }2 s0 v! C6 T U) M0 w4 XLet x = Male, y = Female, z = Child
% j6 `2 S/ L' E5 |# R. x }5 Qtvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
' s8 p! j, s; L* |" [/ ?0 [x + y + z = 100 Formula 2
9 O+ z9 K$ n3 q8 n# l5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
- q" P) h6 G. ?8 e公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
# L8 G. I$ j0 F5.39.217.76Formula 4 can change into 11x + 5y = 100 Formula 57 E3 D! }! h& d8 n$ K$ l
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
, q+ E- D% h4 i+ z, [' R7 Ztvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ g; h' T& f" |Eventually, the answer is 20 female and 80 children and no male. |