That is a very simple mathematics question.
$ U: d4 A* ^) |4 F( E9 j itvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child
* B6 c4 C& W' N% wTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6x + 3y + z/2 = 100 Formula 15.39.217.760 a. N4 R8 C# {2 A# F6 R
x + y + z = 100 Formula 2& Z/ {( U1 X2 V
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.766 t( x# D) B! r% P( h7 `8 L' e
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4公仔箱論壇! j# Y# @7 u! S2 B1 b$ T5 z7 M
Formula 4 can change into 11x + 5y = 100 Formula 5
* K& @ i6 n P6 H# q, L l! T9 `In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
1 ?, L/ p1 K5 a; h1 ETVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.' c$ `+ S" N, G% S9 \
Eventually, the answer is 20 female and 80 children and no male. |