That is a very simple mathematics question.tvb now,tvbnow,bttvb5 L/ Q- B$ P+ u- B2 P/ u
Let x = Male, y = Female, z = Childtvb now,tvbnow,bttvb! y9 y* }& n, \9 s
6x + 3y + z/2 = 100 Formula 1
9 M$ u5 c8 {0 h' n1 H* gtvb now,tvbnow,bttvbx + y + z = 100 Formula 2% Z& X( ^) {4 l- A+ ?8 j# m
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。! Z4 \* F, k% M2 D7 g3 b4 [
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
7 G0 ?# a" B' ~- U9 L- ^Formula 4 can change into 11x + 5y = 100 Formula 5
- L& j, y7 Q/ ^2 Q3 C$ E) o* z! g5.39.217.76In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
& t5 @% [' u7 c$ G公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.3 Q: W1 k9 q, m2 T6 `/ {1 M7 d7 m; o
Eventually, the answer is 20 female and 80 children and no male. |