That is a very simple mathematics question.
0 c7 z* F" h Q" J+ k% I% ^公仔箱論壇Let x = Male, y = Female, z = Child
1 g4 t' B1 R2 ^7 @: v" P$ utvb now,tvbnow,bttvb6x + 3y + z/2 = 100 Formula 1
$ a9 _$ w9 r0 O6 e' nx + y + z = 100 Formula 2' S# s, s; o0 G7 X' N# J
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
: e3 Z6 o, M* _) B( tSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。/ T+ w7 `7 o$ o" o' F* ^: n6 \
Formula 4 can change into 11x + 5y = 100 Formula 5公仔箱論壇$ B% }8 M6 f0 o4 b' {9 \3 h. [
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
) }* p' t+ d5 Y! ?% D公仔箱論壇And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ P: ?0 |- T' ` W+ B6 Etvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |