That is a very simple mathematics question.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。( C* S$ Z5 ]; b7 U
Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。& S! W7 A; N" l( i {. t9 `
6x + 3y + z/2 = 100 Formula 10 X, p5 J' Y c+ O
x + y + z = 100 Formula 2
`4 F" h$ H) b7 t- [5.39.217.76Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.764 w) m/ e* P" h% T) x; z
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4tvb now,tvbnow,bttvb; s1 B# H' k5 D) H
Formula 4 can change into 11x + 5y = 100 Formula 5
) u4 j* v) y1 N; `" gIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76* c8 i5 i6 l" q& x; _) k
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
" Y# j+ a( ]+ H1 \3 b6 X/ f) jEventually, the answer is 20 female and 80 children and no male. |