That is a very simple mathematics question.
) \* p1 q7 a6 x F' htvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child公仔箱論壇- q3 k* ?# w6 ~1 X
6x + 3y + z/2 = 100 Formula 1
* v3 j4 r0 y' o, b' mx + y + z = 100 Formula 2公仔箱論壇% k3 f, H4 K4 ~9 z: e+ V
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
! Y, h. u9 ^; X5 v: F# vSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
7 C/ L3 |6 n7 m" M- wTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb# i% J4 I5 V7 j% e, o) H0 r: F, S; Y
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
. e1 ?/ T5 s$ ^4 p5 M" _tvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb* Q( t+ v. r5 E+ l- m2 ^) F/ `# h
Eventually, the answer is 20 female and 80 children and no male. |