That is a very simple mathematics question.
" N( I: m) m7 Ftvb now,tvbnow,bttvbLet x = Male, y = Female, z = Child公仔箱論壇9 R# l- e7 w8 N3 A
6x + 3y + z/2 = 100 Formula 1
0 {! ^2 Z3 h+ V7 J ktvb now,tvbnow,bttvbx + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ w+ ]+ { `. S1 W" l$ g- J
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.760 g6 E& l7 D/ a b2 O% W
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
* r$ r3 w/ b8 \- f3 U, H( D2 c- |/ g% ztvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb# b2 ~ g' y: _9 X/ ~2 J
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
$ g& M" b1 T! V3 S* CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
- ^' r) e% j) {" b$ Xtvb now,tvbnow,bttvbEventually, the answer is 20 female and 80 children and no male. |