That is a very simple mathematics question.
7 c( f) w/ ?+ [7 G o- U) b9 j5.39.217.76Let x = Male, y = Female, z = Child2 ]# O* Y5 T( e; i7 _' v
6x + 3y + z/2 = 100 Formula 1
, X4 }! T6 w$ E& ?8 {: fx + y + z = 100 Formula 25.39.217.763 o1 r8 }/ w8 R2 R" c
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.76! e$ G8 A3 P% K4 Q* k& g: K
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: ?% D) {2 i+ R9 f7 i7 p: w# T9 ^7 G
Formula 4 can change into 11x + 5y = 100 Formula 50 C6 Z2 J3 }& g1 y; G
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
) J$ p: L2 u2 I8 U3 O8 Vtvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。7 q# n/ h) G* c, y3 v) j
Eventually, the answer is 20 female and 80 children and no male. |