That is a very simple mathematics question.: o. q4 U/ {! o) o6 Z9 E B
Let x = Male, y = Female, z = ChildTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ d% T7 I( i/ P3 {+ {0 F
6x + 3y + z/2 = 100 Formula 1
& L" s+ o0 J- i" E2 {6 gtvb now,tvbnow,bttvbx + y + z = 100 Formula 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。8 u; p! }8 A& ~- `9 g' y+ v
Simplify Formula 2 into z, we get z = 100 - x - y Formula 35.39.217.76. l" z! }) B' ?+ v& C
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
9 D! N3 Y9 f$ C7 j- d* |$ kFormula 4 can change into 11x + 5y = 100 Formula 5
7 b* g2 P& T6 f5 V1 s4 z6 O" CTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.2 ~ u& k, F- A+ Y
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.' r. e9 y2 P6 y$ Q7 N
Eventually, the answer is 20 female and 80 children and no male. |