That is a very simple mathematics question.
% o6 s7 I4 {( }% vTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child
; C) L# w; U' R6x + 3y + z/2 = 100 Formula 1
s# d) W& [/ ?1 N0 {x + y + z = 100 Formula 2tvb now,tvbnow,bttvb- ]; ?! w' p$ u3 p! y
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
4 h" A2 g$ F3 u. f( WTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
9 c5 G" \6 C0 P* C# B( E0 V: ~# MTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Formula 4 can change into 11x + 5y = 100 Formula 5
% K$ s- A; P4 ^2 N* F- J: \# OIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.5.39.217.76: Y( i5 C7 @$ _9 t8 q
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
, h3 p* e& n! e! \) o/ ?: ]4 w) g7 M, i5.39.217.76Eventually, the answer is 20 female and 80 children and no male. |