That is a very simple mathematics question.- W( q; a) O. @( I+ t+ K: C
Let x = Male, y = Female, z = Child
" U+ O& s/ g) M1 I) }5 `公仔箱論壇6x + 3y + z/2 = 100 Formula 1TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% H/ S7 u; z* ?
x + y + z = 100 Formula 2
) w$ ~! p O) M1 d/ ySimplify Formula 2 into z, we get z = 100 - x - y Formula 3
$ d N1 Q6 s2 @3 i8 k: Q8 E公仔箱論壇Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
* P, S% j1 r( K% T6 KFormula 4 can change into 11x + 5y = 100 Formula 5
" _ I- a8 E/ n' @/ o. C. rTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 Z2 y% [5 P7 `% @+ c2 f5 U9 lAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
$ D. b; R) V% O |* K! \; XEventually, the answer is 20 female and 80 children and no male. |