1. divide 6 and 6, both sides will not equal $ @4 S2 D* P7 z6 V/ o2. take any side of the 6, divide then 3 and 3, again both sides will not equal 6 R2 A7 _) `- q; M3. take any 2 and weigh them 1 U1 E$ u2 [, ]; ^tvb now,tvbnow,bttvbif they equal, the one left is the ball.
發表於 2007-6-16 08:33 PM
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