put six on each side first
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from the heavier six, split it to three on each side _! d3 u7 X% Q0 b, B- i/ ~- C$ h
! f: d) F5 j! C" ?( p0 V4 k" m& `5.39.217.76then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |