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why
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let the 12 balls be numbered 1,2,3,4,5,...,12tvb now,tvbnow,bttvb) F% ^7 ~" D1 R2 L1 D; X
weight 1234 with 5678
( `' S+ }6 f5 c6 }6 U% S6 Dtvb now,tvbnow,bttvbcase 1
# Y# c. f. [# E5 r# y. O; c2 |- zif 1234>5678, then weight 125 with 6785.39.217.76! ^: P  M& F. J. Y$ W7 i
if 125>678, then weight 1 with 2
, F; E* Y; Y$ v- Btvb now,tvbnow,bttvbif 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。* A- f+ S3 j3 ~  Y2 P' a9 t
if 125=678, then weight 3 with 9tvb now,tvbnow,bttvb3 o) |* x/ \* Y- y% t
if 3=9 it is 4, else it is 3
! s2 Y* L7 C6 m$ O3 I) X% t公仔箱論壇if 125<678, then ewight 3 with 4TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。% v3 T7 K5 C! B; `
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
9 n& }2 V8 U; }% J7 T5.39.217.76tvb now,tvbnow,bttvb  W: t2 f, {- L4 G0 b- x: x5 z
case 2
/ a+ b* M, a* B/ Z* l5.39.217.76repeat above for 5678 instead of 1234 if 1234<5678
/ y5 ^1 F, X, W' E5.39.217.76tvb now,tvbnow,bttvb1 {2 b$ W1 q; f4 {$ R
case 3" h  O: `7 c  q' v# V3 r
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain公仔箱論壇2 @3 G# X6 Q1 x+ P/ H$ Q2 v, m
0 W/ i! V$ R  d6 q2 Y4 F2 B
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ]
thx
how?
the ball's weight is abnormal than other, not only heaver than other

回復第 1 帖由 MagicAndy 所發的帖子

好贴啊~~~
我都諗到.. 但唔知岩唔岩
实在想不出了
=.=
CC
太简单了吧?
cc
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