返回列表 回復 發帖
答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆! Z2 O* g5 O8 H6 |2 G* ?0 `
共四堆公仔箱論壇  w3 A0 Z$ S( F9 O! r8 d, C8 |
称两次得出异常的在那一堆,其轻重
& d- d7 {3 Q  ^- E$ Ttvb now,tvbnow,bttvb在异常的那一堆中在称一次
) W8 O! p) E3 ^6 l9 q% f# |1 \就可以找到了
divde the 12 balls into 3 sets of 4.
# c/ q' s, e1 l5.39.217.76weight any 2 sets.5.39.217.769 N1 \! o: ]5 J. A2 [
if the 2 sets are equal, then you know the heavy one is in the third
* }9 A" `5 s  r4 _2 I+ l; w- z! \! Pif one of the 2 is heavier, then the heavy one is in that set: Y, I/ C. f- D7 _/ F
then divide the 4 balls into 2.
2 f/ P0 m' ]1 v1 {  f2 F8 fweigh them
. H. g# k4 S) {公仔箱論壇and divide the heavier into 1  L% U1 f4 ^* B2 S. j# b
and weight them.
/ r5 ]0 H- n4 R9 y3 x weighing and get the ans.  
/ e" F$ J9 T9 C% H% o7 o# `in less than 15 secs.
1. 6 aside and weight.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。' i/ Z3 c! U4 \8 B
2. heavier side from (1), 3 aside weight again.5.39.217.761 T! ^/ Y$ ]% \: W
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
3 S2 p( y1 ]. c
6 O7 D, p# x' _2 z公仔箱論壇but i have a question. 重量異常 can be heavier or lighter.... so......
返回列表