lux1261

答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1

lesley

^:)^ >:D<

leekh

thx

jc49

let cc

Special_Forces

not possible

sm911118

不知道要怎麼做阿??

laou

hao

jen198053

there got more simple way to do it, just read my way, the one i answered before

samkk123

the

hakis

see 了

jenfien

第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了

fxenon

how?

nyb

先分3个一堆tvb now,tvbnow,bttvb$ q1 C- ]9 M( R3 b
共四堆
8 G# z" |+ l/ P- J  ^& ETVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。称两次得出异常的在那一堆，其轻重tvb now,tvbnow,bttvb: ^2 u2 s% s, F" V! S$ {8 Z
在异常的那一堆中在称一次tvb now,tvbnow,bttvb7 F# X* x7 s. I7 X) Z# D- a4 B
就可以找到了

ceteriz

divde the 12 balls into 3 sets of 4. 公仔箱論壇6 \& o& d4 q0 b/ r
weight any 2 sets.
! F: ?6 r. v+ K- U8 @TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。if the 2 sets are equal, then you know the heavy one is in the third
5 s! f. ]8 r+ o1 P2 j6 ]9 [8 Vtvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that set公仔箱論壇$ ~) b' y$ d9 q
then divide the 4 balls into 2.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。" K# X& J- ~. z; k9 C8 o$ ^/ O
weigh themtvb now,tvbnow,bttvb* v' x/ ^! x" P
and divide the heavier into 1TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。* _2 M9 {/ x' M/ l* @4 b+ B6 q& u
and weight them.
) b+ k4 i2 _+ Itvb now,tvbnow,bttvb3 x weighing and get the ans.  
4 }; [5 n# K+ J/ q* nTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。in less than 15 secs.

kino_kino

1. 6 aside and weight.
3 j+ J. y; A4 |1 \2. heavier side from (1), 3 aside weight again.tvb now,tvbnow,bttvb! f/ h" [( w) i4 S8 e! m! K6 j
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
2 a3 @" L( e" c. B6 S' G公仔箱論壇
. ^$ S8 w, ?; C2 W4 L% @5.39.217.76but i have a question. 重量異常 can be heavier or lighter.... so......