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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆7 P/ T6 M6 T1 w2 m/ D
共四堆tvb now,tvbnow,bttvb. q  N+ K) c4 f  u0 h
称两次得出异常的在那一堆,其轻重
7 o; n" ]1 T0 b% B0 V9 h  Z' ttvb now,tvbnow,bttvb在异常的那一堆中在称一次5.39.217.761 \, U2 R( X9 t% Q+ \6 a
就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb* k$ [, \: y3 I: D) ?# e  v
weight any 2 sets.公仔箱論壇$ c* P; m% u" b2 ?' |0 K
if the 2 sets are equal, then you know the heavy one is in the third
# R( w0 ]% u, ZTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。if one of the 2 is heavier, then the heavy one is in that set4 d2 r+ C5 g* X. k$ D& f
then divide the 4 balls into 2.tvb now,tvbnow,bttvb1 V' `8 E# y8 L+ u: _  b' K
weigh them
/ ?& K+ b  T0 Q9 vand divide the heavier into 1tvb now,tvbnow,bttvb% M4 l- d8 `- j
and weight them.公仔箱論壇# p9 S% E; S. A) |
3 x weighing and get the ans.  
* s7 ^5 i1 K2 D0 ]TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.
3 Q% n6 R2 j- h$ f7 |0 m4 A2. heavier side from (1), 3 aside weight again.
. `, R- J& @( p" E# ?1 \- h0 a3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 公仔箱論壇& i7 c! ]3 l5 u: i6 z
公仔箱論壇5 M7 \! i' a9 w: g, I0 a1 t: d
but i have a question. 重量異常 can be heavier or lighter.... so......
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