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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
1 c1 e& x. q# g3 E& `: J5.39.217.76将比较重的那份再平均分成两份成一次
! U( `# S" L4 ]公仔箱論壇剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
2 C' ~0 c1 Q3 {$ m# A9 J# @if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇- V; }2 {. V1 T5 ?3 i" L
    then goto 2 - compare rest of(4)  - 2 with 2
: O) j3 f5 Y! i$ k  u# P5.39.217.76           if (left side is more weight)
1 z" |) O" h/ ~7 z8 m; p公仔箱論壇              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answertvb now,tvbnow,bttvb; C. g. c* m' N. w! e- G
          else ( right side is more weight)
9 O5 @, E' d3 S6 v+ J( G              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer, ~2 C2 k3 g: Q% q6 E8 X3 r* ]
else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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