this is too easy!!5 x* `& ^; `/ T- f) V. s
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1. put 6 at each side.. take the one side which is heavier
6 x8 w& r/ C$ m9 R. }5 j& o5.39.217.762. put 3 at each side.. also take the heavier side0 F4 w6 J6 R" b
3. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball.. |
發表於 2009-1-7 05:31 AM
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