hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^
- y: _' |* Z$ J  C9 @4 N& G1st u divide the ball into two group (i group 6 ball)  q; b  ?: t1 Q  H
then 称 them c which side is the heavy
7 ?  G' `4 W( X1 f/ ]  p" E- U$ H  Ttvb now,tvbnow,bttvbthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb1 n3 a& a( X1 r& S
if not balance take the heavy and then
4 _* t! {8 }" Z7 }" C5.39.217.76take the heavy group divided into 2 group i group contain 1 ball than 称 it
" H- L- k" @; M7 {* a$ K9 q; L5 tthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
+ H. O; e7 S0 N0 V. u4 v公仔箱論壇（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边3 n% u) j5 g8 Q7 Y( K# r; {3 z
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me