hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^/ e! ^; f8 o( |1 i7 _* U
1st u divide the ball into two group (i group 6 ball)' l$ y" b- J8 M3 P2 r3 _, u
then 称 them c which side is the heavy
1 h$ D) D3 e' s& Dthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
7 {& m+ v% ]' w6 C' [公仔箱論壇if not balance take the heavy and then
1 u- I5 n$ m: z# T) F$ y9 Y- d公仔箱論壇take the heavy group divided into 2 group i group contain 1 ball than 称 it
9 C9 h! C. r/ C# Rthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
+ r/ ?$ L' c9 W! y! d3 r. y（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
' U9 I, u+ f( ~! u5.39.217.76然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me