hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^5.39.217.76% K: q! S: Z0 ~) S6 Y4 H  A
1st u divide the ball into two group (i group 6 ball)
; {$ n! ^+ V9 Q( r8 v2 C: {$ n0 e公仔箱論壇then 称 them c which side is the heavy
% }" p& r: O' I( i5 N# Y5.39.217.76then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
; S4 Q: N6 L6 Y% C  Xif not balance take the heavy and then tvb now,tvbnow,bttvb6 e! I. {/ q; ^1 o
take the heavy group divided into 2 group i group contain 1 ball than 称 it
9 Z) S% e/ Q- w3 v! [, ethan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 7 P) ^' X6 i3 |
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边公仔箱論壇5 T% |5 k+ \2 _5 o5 X& {1 s. H
然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me