As x is a pure real number, but y only with imaginary part.- }, H0 _" B) j% V
So if want to compare these two numbers, it should compare there magnitude.tvb now,tvbnow,bttvb$ u7 [4 J& `$ k0 y4 a: k
1. x -> 0+0i7 N- l; z( V6 F2 Z; B& r
2. y -> 0+1i7 q% t+ S$ |1 O' Y1 a
/ b J5 \# f( l ?! G& A1 ~' ?5.39.217.76Magnitude of x is |√(0^2 +0^2)| = 0
& @+ [, n C) X6 g1 S; _Magnitude of y is |√(0^2+1^2)| = 1$ h5 C5 u3 H- s
, `" b+ b" G- x( a
So, the magnitude of y >x |
發表於 2012-12-29 07:13 PM
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