put six on each side first
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% l: I: g% d5 x& Utvb now,tvbnow,bttvbfrom the heavier six, split it to three on each side$ B7 u& b& z: g( c
' |1 S% u; g, C; n# }1 E9 c5 s5.39.217.76then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |