put six on each side first
& z1 R( {! j! T8 g# t5.39.217.768 s; `3 E& _, E9 `
from the heavier six, split it to three on each side
4 U. m- ~" [/ V+ g5 C+ o' C/ B r5.39.217.76
4 R8 ^5 j% f+ [0 g+ a' N3 Fthen there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |