let the 12 balls be numbered 1,2,3,4,5,...,125.39.217.76. C+ C' I0 m/ d& }& ~ r3 T
weight 1234 with 5678
" _. P3 p- U8 R; Z' {tvb now,tvbnow,bttvbcase 1
; V( n; H. {$ F' u1 X* a. c) U) Iif 1234>5678, then weight 125 with 678
0 {8 D [/ k+ [0 H' G* `公仔箱論壇if 125>678, then weight 1 with 25.39.217.768 b2 [5 t9 D! b7 _, m
if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
: @- Q. B% l' ?5 j. {if 125=678, then weight 3 with 9
X3 g* G5 G3 j* a* H: oif 3=9 it is 4, else it is 3
0 _/ w+ z6 g. U) T5 k- Vtvb now,tvbnow,bttvbif 125<678, then ewight 3 with 4+ F" X) f" [+ k/ W
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4
8 n% E$ m4 `0 A& t) s: s1 f/ F
; }7 H) c1 j3 A" k0 i# _case 2
3 Z- @3 g0 `5 a! frepeat above for 5678 instead of 1234 if 1234<5678
3 b, i# {2 U! ^+ X2 y) Y$ Ntvb now,tvbnow,bttvb5.39.217.765 E; j' ? K3 i0 Q3 H
case 3/ `3 Z- n A* [4 ? Y6 V
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain5.39.217.761 [6 a- a. F' l0 f5 R
公仔箱論壇" b' d) c5 E; h1 [6 R! q V, J
[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
| 
太简单了吧？