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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
) p! }( Y; M. c- d- F; Q共四堆tvb now,tvbnow,bttvb, ^4 d5 _% Z3 `. a0 B  D# c% t
称两次得出异常的在那一堆,其轻重
- `# Q% a0 E# m/ q在异常的那一堆中在称一次
7 V+ d# Y% |0 d( O就可以找到了
divde the 12 balls into 3 sets of 4. 公仔箱論壇; g: b) F2 [$ x* K( R0 s5 O8 r" X
weight any 2 sets.
8 D+ a( F3 n+ R$ a5 ?tvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
3 t9 o: p& y- O% D5 u; @公仔箱論壇if one of the 2 is heavier, then the heavy one is in that set
# Q" }9 [+ Q  C8 @7 Etvb now,tvbnow,bttvbthen divide the 4 balls into 2.tvb now,tvbnow,bttvb- h* Z/ g+ O* \7 v0 [$ i) h4 s
weigh them% d7 T% ~0 v, k4 g, w
and divide the heavier into 1
& w8 F. |1 K, o. P+ \TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。and weight them.
$ P9 K6 N8 p0 c) R0 t4 @" a2 q3 x weighing and get the ans.  
0 Z; }0 @; |" [' b, L6 {in less than 15 secs.
1. 6 aside and weight.tvb now,tvbnow,bttvb' a6 |4 f6 t" H* q$ b3 p
2. heavier side from (1), 3 aside weight again.
- C" Z* h$ `; r) _4 K% @3 y3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. 5.39.217.76# ?) G+ N! K% z! `3 {

* J# l/ b: c$ n6 l, J2 Vtvb now,tvbnow,bttvbbut i have a question. 重量異常 can be heavier or lighter.... so......
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