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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆! Z6 q4 K! N5 I- A5 Z+ i8 E
共四堆公仔箱論壇4 e+ M; g" L% {+ f6 D# D
称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb$ j& S5 n6 j* z, [+ g
在异常的那一堆中在称一次
; G+ Q* f: e) `% _- `3 O# {) f* etvb now,tvbnow,bttvb就可以找到了
divde the 12 balls into 3 sets of 4. tvb now,tvbnow,bttvb, w+ A1 A3 Q4 y  F
weight any 2 sets.
5 A5 g$ S+ D0 H6 `if the 2 sets are equal, then you know the heavy one is in the third
6 _+ \% r3 L: }) c' Ltvb now,tvbnow,bttvbif one of the 2 is heavier, then the heavy one is in that setTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。1 r+ n6 R2 ]0 C3 S$ }
then divide the 4 balls into 2.
; A( f; C& N  ]. a1 Q公仔箱論壇weigh them
; K- e4 W- b; q  m( H/ Q6 S- J公仔箱論壇and divide the heavier into 1' R" W: `" J9 J: ~8 W8 v
and weight them.tvb now,tvbnow,bttvb, ?+ O0 R/ a- w
3 x weighing and get the ans.  
$ s9 c- @7 P2 b' l# qTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。in less than 15 secs.
1. 6 aside and weight.
9 O. ^3 I+ b2 x7 C0 Q* g* G' Ztvb now,tvbnow,bttvb2. heavier side from (1), 3 aside weight again.公仔箱論壇" T* S/ i, Q5 s3 O
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. tvb now,tvbnow,bttvb: Y0 E7 v& y6 }! |9 S' C
; q$ W9 O+ a& k/ ?( J2 G0 ?7 n
but i have a question. 重量異常 can be heavier or lighter.... so......
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