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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆9 k, i; d6 g4 {: L, B4 A! R# p
共四堆tvb now,tvbnow,bttvb0 }% |! t1 ]) v) ?- i& A" K8 }# E
称两次得出异常的在那一堆,其轻重
/ I+ y+ L: l4 x7 b0 D+ F5.39.217.76在异常的那一堆中在称一次
% y; ?; D) q: K! q2 e就可以找到了
divde the 12 balls into 3 sets of 4. TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。+ J7 u5 b* T  j( y0 m' g
weight any 2 sets.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# R$ R7 F0 y! c% N& q9 `- {* o
if the 2 sets are equal, then you know the heavy one is in the third& X( x7 K, f# ^& r% t. ^% Q4 c
if one of the 2 is heavier, then the heavy one is in that set& X+ E( _; y; e) v' Y
then divide the 4 balls into 2.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: N( X& y: o5 i# D- R
weigh themtvb now,tvbnow,bttvb9 D/ A0 }! j, S7 N, e$ B
and divide the heavier into 1& \/ b7 D) \! E9 B
and weight them.
. ^1 m1 I1 y% d3 x weighing and get the ans.  5.39.217.768 d, j4 Z! T! F
in less than 15 secs.
1. 6 aside and weight.
. G# Z2 Z* l6 I* i, e2. heavier side from (1), 3 aside weight again.
0 J  q% p2 F+ n* u6 {3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. - c$ u% ?. E3 d5 J3 X5 G  M# W0 Z
6 g7 H  ?5 Z6 r, [0 n8 {
but i have a question. 重量異常 can be heavier or lighter.... so......
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