zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。$ `' K; _# I; R3 A' C5 b/ y* Q
将比较重的那份再平均分成两份成一次: k, k5 m; c; u
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
: H# N; O) x" M+ _if  (4v4)= same that means the rest of 4 is got more weight0 R$ V6 P% f! Z5 o% s
    then goto 2 - compare rest of(4)  - 2 with 2 tvb now,tvbnow,bttvb8 Q, B( T5 y5 U/ p/ l
           if (left side is more weight)0 g( s# i) \6 o
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
5 S( C0 m( ~! M7 }; P公仔箱論壇          else ( right side is more weight)4 O9 Z% i1 C( @+ x7 O' ~
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
9 n) ~2 f, C: e; a2 e6 e0 z5.39.217.76else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。