zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次
! v! N- p$ Z7 u9 g5 L; J8 k# u. e公仔箱論壇将比较重的那份再平均分成两份成一次5.39.217.76% x+ J  Q* Z% B. v
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 40 r" z% R# m0 S' y* x
if  (4v4)= same that means the rest of 4 is got more weight5.39.217.76$ c: {. B. f' o# S( K2 q! O5 D/ @
    then goto 2 - compare rest of(4)  - 2 with 2
. }9 Z' i0 P1 G( t, C5 f           if (left side is more weight)5.39.217.768 F, ]2 B: ~, y& ~5 e+ k
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer公仔箱論壇$ ?" ~1 M8 G% m' ~* D
          else ( right side is more weight)
) Y6 D% _9 R/ A$ a6 X6 p              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer7 G8 D' {, \  [" N; U
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。