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that's easy, i only took 30secs of it!
. h) n# z* e" G1st: seperate 2 groups of the ball, which are 6 each of the group, scal them up and must be one of them are heavier than the another, and then
; U9 M2 D$ l2 n  K5 ]! ^tvb now,tvbnow,bttvb2nd: seperate the heavier group's ball into 3 balls each and scale again, then we can tell one of these will heavier than the another and took the heavier group's ball into three group of one of each in the group, and scal the 3rd time, if the result of 3rd scal come with eaven that meants the 3rd ball is the heavy one out of the 12 balls, or if the result come of one of them is heavy then the one on the scal is heaier than the 11balls!  Q.E.D.
see answer
3对3对3 就可以知道其中一组3个有问题各,再拿3个里面的2个来平衡那不就OK拉。。
I would like to know the answer
I really don't see how u can do it
其實點解咁多人話好易??唔明~
好易喎~~~

回應 MagicAndy 第 1 篇文章

先33>>再由33取1加入成6>>再22比>>>再由22比沒拿的2取1>>將22比取1並將其中一個對調
thanks for sharing.

回應 MagicAndy 第 1 篇文章

let's see
一半 一半 以此做下去  最後可得異常
超難的!! THX
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