hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^+ Q/ ?& D1 q, [0 Y; `! a- V) C
1st u divide the ball into two group (i group 6 ball)
$ ^, z1 K/ l/ O. ?5.39.217.76then 称 them c which side is the heavy
1 ?5 W4 B* z. n* g' ?( p! f公仔箱論壇then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
5 J& U6 l& N" a! U; I1 ~% p3 yif not balance take the heavy and then
. z7 S! _" z" j: q* Q5.39.217.76take the heavy group divided into 2 group i group contain 1 ball than 称 it
5 S: t. {1 C4 v" l/ ytvb now,tvbnow,bttvbthan the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 公仔箱論壇9 \5 `& Y% M3 M! i: l, W7 D
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
, T- E: q. Z2 f: U$ r- v然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me