i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb% b9 _/ ^0 m. R5 E. a1 \7 Y( p: M
1st u divide the ball into two group (i group 6 ball)
' S; s, W0 Y5 @: D2 |then 称 them c which side is the heavy
& k0 K5 E+ _9 J3 d* \9 {. C: a pthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 5.39.217.76# e) U/ q7 s/ p& m0 Q
if not balance take the heavy and then
; i8 W; l; {. M7 j, ~& btvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
$ H2 s- }- a8 v; W. R# Z5.39.217.76than the heavy ball is the ball u wan |