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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^tvb now,tvbnow,bttvb% b9 _/ ^0 m. R5 E. a1 \7 Y( p: M
1st u divide the ball into two group (i group 6 ball)
' S; s, W0 Y5 @: D2 |then 称 them c which side is the heavy
& k0 K5 E+ _9 J3 d* \9 {. C: a  pthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 5.39.217.76# e) U/ q7 s/ p& m0 Q
if not balance take the heavy and then
; i8 W; l; {. M7 j, ~& btvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it
$ H2 s- }- a8 v; W. R# Z5.39.217.76than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。: k+ g# Z  o% \4 K" T
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
* r2 U! H2 n# }tvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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