hoeteck

i wan to know

wenlove08

thx.~

caseylee0427

thank you for sharing

rock5356466

look at it

leo_04236

i noe de ans cauz 1 do b4 already ^^公仔箱論壇$ L, t. Y! F1 ~5 m
1st u divide the ball into two group (i group 6 ball)6 H* @& Q0 ~* m- K
then 称 them c which side is the heavy
3 ~+ f# S3 ^# ^" o  U5 @9 xthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group
6 u8 C2 m9 n" \, D* oTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。if not balance take the heavy and then ! K) ?7 a! V2 q' y& O  r
take the heavy group divided into 2 group i group contain 1 ball than 称 it $ S5 Z/ O; _7 a8 O+ b1 n+ y" v1 K! Q
than the heavy ball is the ball u wan

sam5881

how??????????

ar_yuo

Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:

单身汉

分三次算的话，每次分四粒来算，意思说当有一边较重时，只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: 5.39.217.76+ {* C/ J2 I6 l5 Y
（不知各位知不知道小弟说的解答，因为小弟不擅长解说）

ldcloud

thx 4 sharing

烟灰缸

顶．．．．．．

烟灰缸

顶．．．．．．．

haharinny

简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2：2的称。。又知道异常的一边
1 u; R: m7 Z. D6 I: S  h然后。。1：1。。就知道了··

htq771112

看解答!!!!!!!!!!!!!!

puki

cccccc

Hikouseki

idk..show me