put six on each side first0 G- X6 N/ g' u9 W
* Y% ~9 f5 m0 y1 M9 Mfrom the heavier six, split it to three on each side5.39.217.76* o* I# a* X4 G# X0 u ~
' k' x# X2 a( o0 T5.39.217.76then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |