let the 12 balls be numbered 1,2,3,4,5,...,12
/ Q" Z9 V) d1 r( | \) Q; Fweight 1234 with 5678, \, ^; Y0 x: u' c; ~ E
case 1
5 z$ B1 L& a3 pif 1234>5678, then weight 125 with 678
2 X8 H2 d9 A. _+ T$ [if 125>678, then weight 1 with 2
+ G, a8 Y2 j6 z7 ?* l4 T7 t3 a5.39.217.76if 1>2 it is 1, if 1=2 it is 5, if 1<2 it is 2
! w6 {, u% K; X+ K( }8 cif 125=678, then weight 3 with 9
6 E2 z" }6 n" ctvb now,tvbnow,bttvbif 3=9 it is 4, else it is 3
1 M- e2 c4 ]" g6 ]if 125<678, then ewight 3 with 47 H1 G# L- M# M# D7 c8 Y
if 3>4 it is 3, if 3=4, it is 5, if 3<4, it is 4tvb now,tvbnow,bttvb: z; A& |' j7 c; i7 M5 O
! i3 S. v& [1 d. j( ycase 25.39.217.768 v. n+ N- u' F* ?
repeat above for 5678 instead of 1234 if 1234<5678
; F3 F9 ?0 \# E& t0 p& z% sTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' _% F6 k" Z5 ], O
case 37 y( \& ^; {& x* N
1234=5678, this case u only have 9 10 11 12 as possible, this is easy enough that i don't need to explain公仔箱論壇# e5 H( H7 t) _6 Y
' ]9 g. S8 B1 ]/ U公仔箱論壇[ 本帖最後由 l0709394 於 2007-5-8 10:15 AM 編輯 ] |
發表於 2007-5-7 11:25 AM
| 
太简单了吧？