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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆5.39.217.76: T' W4 o3 w2 \* M# U) I2 W
共四堆
5 v. o$ i$ Q7 D" T( k称两次得出异常的在那一堆,其轻重tvb now,tvbnow,bttvb( P; m& m0 n- l: ]8 {
在异常的那一堆中在称一次
8 d! y( _+ K' p4 q2 s" f* hTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。就可以找到了
divde the 12 balls into 3 sets of 4.
  t  ~& F9 X6 O: j0 r3 [weight any 2 sets.
7 W" t* v$ V" S' X6 e# |8 Y/ Mtvb now,tvbnow,bttvbif the 2 sets are equal, then you know the heavy one is in the third
+ [3 Y: l( m  o' I% t( S/ N% {if one of the 2 is heavier, then the heavy one is in that set7 ~5 R( j3 ~8 _# @$ x* ]- J
then divide the 4 balls into 2.
" ?$ F' X' d  O2 S0 a: U' k! z公仔箱論壇weigh them5.39.217.765 T9 @/ y! n  k$ {3 u
and divide the heavier into 1公仔箱論壇; s. C6 p6 \$ S1 r, p* v
and weight them.
: a$ P6 m$ t  [) L5 V公仔箱論壇3 x weighing and get the ans.  
. v8 o4 X2 ?: f, r; A5.39.217.76in less than 15 secs.
1. 6 aside and weight.. C+ ~9 ]& ~4 J! R' {" s! a0 {
2. heavier side from (1), 3 aside weight again.
# [0 r$ W" W: ~- b0 KTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one.
+ x" J3 v, O: ^: @  q, }
% k- h8 M% v4 B% x8 w% O# D* a& O公仔箱論壇but i have a question. 重量異常 can be heavier or lighter.... so......
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