1 - compare 4 with 4
4 f# {) e. d; O- j/ O rif (4v4)= same that means the rest of 4 is got more weight( U$ C- H6 j# d( y+ \
then goto 2 - compare rest of(4) - 2 with 2
4 G, F' [* [; o" E7 j$ ~ if (left side is more weight)5.39.217.761 t/ F1 j6 x ?' s
then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
/ X. d/ s7 T( Y+ Ftvb now,tvbnow,bttvb else ( right side is more weight); N1 @5 ?: M/ S+ ~) q! p% o
then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
/ V: P7 _. C! \5 y5 u' M5.39.217.76else ( the left 4) then compare with above , or right 4 also can compare above method... |