zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次tvb now,tvbnow,bttvb( v% W( A* P# c  E& i$ q  G
将比较重的那份再平均分成两份成一次' b% _/ _3 _, S
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
. x! r( \1 A* k3 a9 E9 |9 Dif  (4v4)= same that means the rest of 4 is got more weight
- B7 |% z& g4 x% m6 L4 ?; bTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。    then goto 2 - compare rest of(4)  - 2 with 2
. q6 q9 ~, F4 ^0 g5 U1 e" N9 Jtvb now,tvbnow,bttvb           if (left side is more weight)
- l7 b5 w2 f. b* r4 n# z* J6 C2 V5.39.217.76              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
- r( j* ~, m( _" v公仔箱論壇          else ( right side is more weight)# D- |4 d" \0 l8 z$ S
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answertvb now,tvbnow,bttvb, Q; d! l( _$ o+ L# E
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。