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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次公仔箱論壇! o8 Q0 W4 X6 q* u8 I
将比较重的那份再平均分成两份成一次
9 E" ~4 ?" y2 J) ^5 I5 D5.39.217.76剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4
4 f# {) e. d; O- j/ O  rif  (4v4)= same that means the rest of 4 is got more weight( U$ C- H6 j# d( y+ \
    then goto 2 - compare rest of(4)  - 2 with 2
4 G, F' [* [; o" E7 j$ ~           if (left side is more weight)5.39.217.761 t/ F1 j6 x  ?' s
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
/ X. d/ s7 T( Y+ Ftvb now,tvbnow,bttvb          else ( right side is more weight); N1 @5 ?: M/ S+ ~) q! p% o
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
/ V: P7 _. C! \5 y5 u' M5.39.217.76else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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