zzzhao

see xia da an

yaukinman

want to know

zb7803

我来看看

lkhlewis

青蓮居士

check ans..

mkl2345

6 and 6 then 3 and 3 then 1 and 1

gg2968

5識答？

pyhzf

thank you

XYZCrux

将12个乒乓球分成平均两份，称一次2 h" P/ S- Z: ?# `2 ~  u
将比较重的那份再平均分成两份成一次5.39.217.767 X# x% ~* `# _3 x: d4 Y* R- G
剩下3个随意拿两个来称，如果天平平衡就是第三个，如果不平衡就是重的那个

wtfka

thank

agnesium

Thanks!

ban0212

第一次系一边四个，一边四个秤既

westgun

1 - compare 4 with 4
8 H9 ]; W6 Q9 O; `0 q公仔箱論壇if  (4v4)= same that means the rest of 4 is got more weight
. a$ z/ T2 j6 [8 p% U公仔箱論壇    then goto 2 - compare rest of(4)  - 2 with 2
# p! I  q+ l+ J- A2 `           if (left side is more weight)
) W; ?# N, }* d, Y  O  w1 |! Z公仔箱論壇              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
$ T1 [0 C, p2 I7 r3 e" W/ N& s  I5.39.217.76          else ( right side is more weight)
' I: w4 |5 L  z0 @2 d公仔箱論壇              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer5.39.217.760 E' |% `9 F9 k& L* K
else ( the left 4) then compare with above  , or right 4 also can compare above method...

ywl01

想了好久都不行

zhengfaxuezi

我的做法与4楼的做法一致，这样应该可以排除出来。但这个题目有个漏洞，只说重量异常，没说是重了，还是轻了。