this is too easy!!
9 p% n \: Z3 p; ]) \: R
2 [( l) m V/ P5 L/ E+ Y9 S$ ~1. put 6 at each side.. take the one side which is heavier9 D0 e0 O p5 `% x
2. put 3 at each side.. also take the heavier sidetvb now,tvbnow,bttvb/ V- X0 j) S$ O- V
3. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball.. |
發表於 2009-1-7 05:31 AM
| 
