Well..divided into 6/6 first to define a heavier group is certainly right. Randomly select 3/3 will result another heavier group. 2 M$ C! x/ z5 T1 ?, LThe problem is we don't know the weight of each individual ball, so it will not be accurate to figure out which ball is irregular by only weight them once. $ H2 t5 [9 Y, @' w$ n9 q5 O+ Ptvb now,tvbnow,bttvb